Answer:
0.22 b
Explanation:
Quadrupole moment of the nucleon is,
And also,
And, 
Now,
For Bismuth 
and A is 209.
Therefore, the expected value of quadrupole is 0.22 b which is quite related with experimental value which is 0.37 b
Answer:
16 m/s.
Explanation:
The following data were obtained from the question:
Mass of truck = 5000 Kg
Velocity of truck = 8 m/s
Mass of car = 2500 kg
Velocity of car =..?
Next, we shall determine the momentum of the truck. This can be obtained as follow:
Mass of truck = 5000 Kg
Velocity of truck = 8 m/s
Momentum of truck =.?
Momentum = mass × velocity
Momentum = 5000 × 8
Momentum of the truck = 40000 Kg.m/s
Finally, we shall determine the velocity of the car as follow:
From the question given above, we were told that the car and truck has the same momentum.
This implies that:
Momentum of the truck = momentum of car = 40000 Kg.m/s
Thus, the velocity of the car can be obtained as shown below:
Mass of car = 2500 kg
Momentum of the car = 40000 Kg.m/s
Velocity of car =..?
Momentum = mass × velocity
40000 = 2500 × velocity
Divide both side by 2500
Velocity = 40000/2500
Velocity = 16 m/s
Therefore, the velocity of the car is 16 m/s.
1.The answer is True
2.The answer is False
They have expression<span>, modesty, sex appeal, </span><span>simplicity.</span>
Oxygen is diatomic, so its degree of freedom, (f1)= 5,
also its number of moles, n1= 1
Helium is monoatomic, so its degree of freedom (f2)= 3
and its number of moles given is, n2=2
Now using formula of effective degree of freedom of mixture, (f), we have:
f= (f1n1+f2n2)/(n1+n2)
= (5*1 + 3*2)/ (1+3)
=11/3
Also, from first law of thermodynamics;
U= n Cv. T = nRT(f2)
or, Cv = R. (f/2) (n & T cancel)
We know f=11/6,
substituting the value in above relation, we have:
Cv= R. 11/3*2
= R. 11/6
Also, Cp-Cv = R
or, Cp- R.(11/6)= R
or, Cp= R(11/6 )+1
= 17/6 R
Therefore, Cp/Cv = 17/11
