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3 years ago

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cuantos gramos de oxígeno necesarios para que reaccionen completamente 28 gramos de etanol (c2h5oh) en la reaccion de combustion

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1 answer:

tigry1 [53]3 years ago

4 0

Answer:

I dont speak this language sorry :(

Explanation:

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Which is the balanced chemical equation representing the reaction between

Citrus2011 [14]

Answer:

The correct option is OA.

C2H4O2 + NaHCO3 - NaC2H302 + H2O + CO2

Explanation:

To solve this you have to check the number of elements in both sides of the equation.

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3 years ago

Read 2 more answers

How many grams of water can be formed from the reaction of 8.76 grams of H2 with 10.5 liters of O2 (at STP) according to the bal

Kisachek [45]

Answer:

16.9g of H₂O can be formed

Explanation:

Based on the chemical reaction, 2 moles of H₂ react per mole of O₂. To anser this question we must find limiting reactant converting the mass and volume of each reactant to moles:

<em>Moles H₂ -Molar mass: 2.016g/mol-:</em>

8.76g * (1mol / 2.016g) = 4.345 moles

<em>Moles O₂:</em>

PV = nRT

PV/RT = n

P = 1atm at STP

V = 10.5L

R = 0.082atmL/molK

T = 273.15K at STP

n = 1atm*10.5L / 0.082atmL/molK*273.15K

n = 0.469 moles of oxygen

For a complete reaction of 4.345 moles moles of hydrogen are required:

4.345 moles H2 * (1mol O2 / 2mol H2) = 2.173 moles of O2 are required. As there are just 0.469 moles, Oxygen is limiting reactant

Now, 1 mole of O2 produce 2 moles of H2O. 0.469 moles will produce:

0.469 moles O₂ * (2 moles H₂O / 1mol O₂) = 0.938 moles H₂O.

The mass is -Molar mas H₂O = 18.01g/mol-:

0.938 moles * (18.01g/mol) =

<h3>16.9g of H₂O can be formed</h3>

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3 years ago

What is pseudoscience?how is it different from non-science?

Anika [276]

Answer:

Pseudoscience is statements claiming to be backed by science, however don’t conform to the scientific method or present facts (most commonly are misconceptions). Whereas, non-science is the of non-scientific subjects, such as; art, history and religion.

Explanation:

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3 years ago

3. Two people are playing tug of war. One person pulls to the right with 32 N of force. The other person pulls to the left with

SVETLANKA909090 [29]

The net force = -5 N

The direction : to the left(negative sign)

<h3>Further explanation </h3>

Net force : the sum of all forces acting on an object

Force is a vector quantity that has both magnitude and direction,

We agree that the move up and to the right is a positive sign, while down and to the left is a negative sign.

The direction of the force (horizontal motion) is to the right (+32 N), and to the left (-37 N), so the net force :

$\tt \sum F=F~right-F~left\\\\\sum F=32-37\\\\\sum F=-5~N$

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3 years ago

Hydrocyanic acid, HCN, is a weak acid. (a) Write the chemical equation for the dissociation of HCN in water. (b) Identify the Br

12345 [234]

Answer: a) $HCN(aq.)+H_2O\rightleftharoons H_3O^+(aq.)+CN^-(aq.)$

b) $HCN$ : acid $CN^-$ :conjugate base.

And, $H_2O$ : base $H_3O^+$ : conjugate acid.

c) $HCN(aq.)+NaOH(aq)\rightleftharoons NaCN(aq.)+H_2O(l)$

d) $NaCN(aq)\rightarrow Na^+(aq.)+CN^-(aq)$

e) $NaCN(aq)+HCl(aq)\rightarrow NaCl(aq.)+HCN(aq)$

Explanation:

a) Weak acid is defined as the acid which does not completely dissociates when dissolved in water. They have high pH. These releases $H^+$ ions in their aqueous states.

The equation for the dissociation of $HCN$ acid is given by:

$HCN(aq.)+H_2O\rightleftharoons H_3O^+(aq.)+CN^-(aq.)$

b) According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given chemical equation:

$HCN$ is loosing a proton, thus it is considered as an acid and after losing a proton, it forms $CN^-$ which is a conjugate base.

And, $H_2O$ is gaining a proton, thus it is considered as a base and after gaining a proton, it forms $H_3O^+$ which is a conjugate acid.

c) Neutralization reaction is a reaction in which an acid reacts with base to produce salt and water.

$HCN(aq.)+NaOH(aq)\rightarrow NaCN(aq.)+H_2O(l)$

d) The chemical equation for dissociation of $NaCN$ in water.

$NaCN(aq)\rightarrow Na^+(aq.)+CN^-(aq)$

e) The chemical equation for the reaction of $NaCN$ and $HCI$

$NaCN(aq)+HCl(aq)\rightarrow NaCl(aq.)+HCN(aq)$

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3 years ago