1. At room temperature, air is usually a (solid, liquid, gas).

A thermometer is placed in a beaker full of water that has been sitting on the lab table for a few hours. The beaker is placed o

krek1111 [17]

Based on the information I would assume B, 73 degrees...

It shouldn't be A, 4 minutes on the burner should increase the temperature.

If it were D, it would be beyond boiling, and water takes a decent amount of energy to heat, D should be all vapor.

Same logic for C, it's basically almost boiling.

I would say 73 degrees seems most reasonable for 4 minutes.

7 0

4 years ago

Read 2 more answers

What is the concentration (m) of sodium ions in 4.57 l of a.847 m na3p solution?

drek231 [11]

A group of environmentalists were discussing the benefits and drawbacks associated with using fossil fuels. Which argument best fits the conversation?
Fossil fuels are cheaper than alternative forms of energy.Fossil fuel reserves will never be depleted.Fossil fuels are easily renewed. Fossil fuel use does not affect the environment.

8 0

3 years ago

In a science lab, a student heats up a chemical from 10 °C to 25 °C which requires thermal energy of 30000 J. If mass of the obj

olganol [36]

Answer:

The specific heat capacity of the object is 50 J/g°C ( option 4 is correct)

Explanation:

Step 1: Data given

Initial temperature = 10.0 °C

Final temperature = 25.0 °C

Energy required = 30000 J

Mass of the object = 40.0 grams

Step 2: Calculate the specific heat capacity of the object

Q = m* c * ΔT

⇒With Q = the heat required = 30000 J

⇒with m = the mass of the object = 40.0 grams

⇒with c = the specific heat capacity of the object = TO BE DETERMINED

⇒with ΔT = The change in temperature = T2 - T2 = 25.0 °C - 10.0°C = 15.0 °C

30000 J = 40.0 g * c * 15.0 °C

c = 30000 J / (40.0 g * 15.0 °C)

c = 50 J/g°C

The specific heat capacity of the object is 50 J/g°C ( option 4 is correct)

3 0

3 years ago

Dinitrogen pentoxide gas is formed by the reaction of nitrogen trioxide gas and nitrogen dioxide gas balanced equation

leonid [27]

Answer:

Balanced chemical equation:

NO₂ + NO₃ → N₂O₅

Explanation:

Chemical equation:

NO₂ + NO₃ → N₂O₅

Balanced chemical equation:

NO₂ + NO₃ → N₂O₅

Nitrogen trioxide gas combine with nitrogen dioxide gas and form nitrogen pentoxide.

This is the simple synthesis reaction in which two substance combine to form a new substance.

Synthesis reaction:

It is the reaction in which two or more simple substance react to give one or more complex product.

General chemical equation:

A + B → AB

A and B are reactants that combine to form AB product.

7 0

3 years ago

What volume of 0.152 M KMnO4 solution would completely react with 20.0 mL of 0.381 M FeSO4 solution according to the following n

ANEK [815]

Answer: The volume of permanganate ion (potassium permanganate) is 10.0 mL

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .....(1)

Molarity of ferrous sulfate solution = 0.381 M

Volume of solution = 20.0 mL = 0.020 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$0.381M=\frac{\text{Moles of ferrous sulfate}}{0.020L}\\\\\text{Moles of ferrous sulfate}=(0.381mol/L\times 0.020L)=0.00762mol$

For the given chemical equation:

$5Fe^{2+}+8H^++MnO_4^-\rightarrow 5Fe^{3+}+Mn^{2+}+4H_2O$

By Stoichiometry of the reaction:

5 moles of iron (II) ions (ferrous sulfate) reacts with 1 mole of permanganate ion (potassium permanganate)

So, 0.00762 moles of iron (II) ions (ferrous sulfate) will react with = $\frac{1}{5}\times 0.00762=0.00152mol$ of permanganate ion (potassium permanganate)

Now, calculating the volume of permanganate ion (potassium permanganate) by using equation 1, we get:

Molarity of permanganate ion (potassium permanganate) = 0.152 M

Moles of permanganate ion (potassium permanganate) = 0.00152 mol

Putting values in equation 1, we get:

$0.152mol/L=\frac{0.00152mol}{\text{Volume of permanganate ion (potassium permanganate)}}\\\\\text{Volume of permanganate ion (potassium permanganate)}=\frac{0.00152mol}{0.152mol/L}=0.01L=10.0mL$

Hence, the volume of permanganate ion (potassium permanganate) is 10.0 mL

3 0

3 years ago

1. At room temperature, air is usually a (solid, liquid, gas).​

1. At room temperature, air is usually a (solid, liquid, gas).