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Anna007 [38]
3 years ago
10

A metal spoon becomes hot after being left in a pan of boiling water. this is an example of _____. conduction reflection radiati

on convection
Physics
2 answers:
IRISSAK [1]3 years ago
6 0
Two methods of transfer of heat are involved in this process: conduction and convection.

In fact, the metal spoon is heated by conduction because the molecules of the boiling water collide with the molecules of the spoon, releasing heat to it; and also by convection, because in the pot of boiling water masses of hot water goes upward and they give their heat to the spoon, then these masses become cooler and they go down, replaced by other masses of hot water.
LenaWriter [7]3 years ago
6 0

Answer:

conduction

Explanation:

When metal spoon is placed in a pan of boiling water we can feel that after some time the metal spoon temperature will increase.

Here as we know that here heat is transferred from boiling pan to metal spoon due to which its temperature got increased.

Now there are three possible ways to transfer heat

1. Conduction

2. Convection

3. Radiation

Here radiation do not need any medium to transfer heat so it is not possible here

Convection need either liquid or gas while here we have metal spoon to transfer heat so this is also not possible here

So correct way to transfer heat is CONDUCTION

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Answer:

The observed wavelength on Earth from that hydrogen atom is 5.24\times 10^{-7}\ m.

Explanation:

Given that,

The actual wavelength of the hydrogen atom, \lambda_a=5.13\times 10^{-7}\ m

A hydrogen atom in a galaxy moving with a speed of, v=6.65\times 10^6\ m/s

We need to find the observed wavelength on Earth from that hydrogen atom. The speed of galaxy is given by :

v=c\times \dfrac{\lambda_o-\lambda_a}{\lambda_a}

\lambda_o is the observed wavelength

\lambda_o=\dfrac{v\lambda_a}{c}+\lambda_a\\\\\lambda_o=\dfrac{6.65\times 10^6\times 5.13\times 10^{-7}}{3\times 10^8}+5.13\times 10^{-7}\\\\\lambda_o=5.24\times 10^{-7}\ m

So, the observed wavelength on Earth from that hydrogen atom is 5.24\times 10^{-7}\ m. Hence, this is the required solution.

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As the average kinetic energy of a substance increases, the tempature of the sample
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2 years ago
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gulaghasi [49]

Answer:

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A very long uniform line of charge has charge per unit length λ1 = 4.68 μC/m and lies along the x-axis. A second long uniform li
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Answer:

E_{net} = 6.44 \times 10^5 N/C

Explanation:

As we know that electric field due to infinite line charge distribution at some distance from it is given as

E = \frac{2k \lambda}{r}

now we need to find the electric field at mid point of two wires

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now plug in all data

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