The record for the highest speed achieved in alaboratory for a
1 answer:
Answer:
0.000234 seconds
Explanation:
Since the row is 0.15m, its radius of rotation must be 0.15 / 2 = 0.075 m
We can start by calculating the angular speed of the rod:
Since one revolution equals to 2π rad. The speed in revolution per second must be
26800 / 2π = 4265 revolution/s
The number of seconds per revolution, or period, is the inverse:
1/4265 = 0.000234 seconds
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Answer:
45.9m
Explanation:
Given parameters:
Final velocity = 30m/s
Initial velocity = 0m/s
Unknown:
Height of fall = ?
Solution:
The motion equation to solve this problem is given below;
V² = U² + 2gH
V² = 0 + (2 x 9.8 x H)
30² = 19.6H
H = = 45.9m
Answer:
Explanation:
The problem is based on vibration in string .For it the formula is as follows :
n = k √T , n is frequency of fundamental tone , k is constant for a string of given length and T is tension in the string .
In the first case weight of sphere is equal to tension .
weight = volume of sphere x density of copper x g
= v x 8960 x g
Putting the values
300 = k √ (v x 8960 x g)
300 = k √ 87808v
When the sphere is half submerged
tension is equal to apparent weight of sphere in water
= v x 8960 x g - .5 v x 1000 x 9.8 , v is volume
= 82908v
for second case
n = k √ 82908v
dividing the two equations
n / 300 =
= .9716
n = 291.5 Hz .