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Novosadov [1.4K]
4 years ago
14

There is a 12 v potential difference between the positive and negative ends of the jumper cables, which are a short distance apa

rt. an electron at the negative end ready to jump to the positive end has a certain amount of potential energy. on what quantities does this electrical potential energy depend? view available hint(s)
Physics
1 answer:
steposvetlana [31]4 years ago
4 0
The electric potential energy of the electron depends on the potential difference applied between the two ends of the cable. Indeed, the electric potential energy of a charge is given by
U=q \Delta V
where q is the magnitude of the charge, while \Delta V is the potential difference applied. So, U depends on \Delta V.
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A current of 0.92 A flows past a point in a circuit? How much charge, in units of Coulombs, passes that point in one minute?
Alisiya [41]
<h3><u>Answer;</u></h3>

<u>  = 55.2 Coulombs </u>

<h3><u>Explanation</u>;</h3>

We can determine Charge using the formula

Q =It, where Q is the amount of charge in Coulombs, I is the current in amperes and t is the time in seconds.

I = 0.92 amperes, t = 1 minute or 60 seconds

Charge = 0.92 × 60

          <u>  = 55.2 Coulombs </u>

7 0
3 years ago
A pendulum has a period of 0.500. What is its length?
qwelly [4]
It's about 6 cm long
6 0
3 years ago
What effect does friction have on a moving object? i forgot this pls help tyy
Vsevolod [243]

Answer:it causes the moving object to slow eventually stop

Explanation:

5 0
3 years ago
A TV with a power rating of 267 W uses 1.9 kWh in one day. How many hours was the TV during that day?
Aleonysh [2.5K]
1.9kWh/0.267kW = 7.11 hours
4 0
3 years ago
A sphere of radius 1.59 cm and a spherical shell of radius 7.72 cm are rolling without slipping along the same floor. The two ob
valina [46]

Answer: 4.86

Explanation:

sphere moment of Inertia Iₑ = (2/5)mrₑ²

Let the sphere of radius 1.59 cm be x

Let the spherical shell of radius 7.72 cm be y, so that

Iₑ(x) = 2/5 * m * 1.59²

Iₑ(x) = 2/5 * m * 2.5281

Iₑ(x) = 1.011m

Iₑ(y) = 2/5 * m * 7.72²

Iₑ(y) = 2/5 * m * 59.5984

Iₑ(y) = 23.84m

Also, the angular speed of the sphere's would be ωₑ(x) and ωₑ(y)

total k.e = rotational k.e + linear k.e

for sphere = ½Iₑωₑ² + ½mωₑ²rₑ²

For sphere x

{ωₑ²[ 1.011 + 1.59²]} =

ωₑ²(1.011 + 2.5281) =

ωₑ²(3.5391)

For sphere y

{ωₑ²[ 23.84 + 7.72²]} =

ωₑ²(23.84 + 59.5984) =

ωₑ²(83.4384)

If the ratio of x/y = 1, then

ωₑ(x)²(3.5391) / ωₑ(y)²(83.4384) = 1

ωₑ(x)²(3.5391) = ωₑ(y)²(83.4384)

[ωₔ(x)/ωₑ(y)]² = [83.4384] / [3.5391] ~= 23.5762

[ωₔ(x)/ωₑ(y)] = √(23.5762)

[ωₔ(x)/ωₑ(y)] = 4.86

3 0
3 years ago
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