The answer is λ₂ = 6.48 cm or 6.52 cm.
The out-of-tune guitar may have a wavelength between "6.48 cm" and "6.52 cm."
fb = |f2 − f1|
f₁ = 343/0.064
= 5276Hz
f₂ = 5276.9 Hz ± 17 Hz
f₂ = 5293.9 Hz or 5259.9 Hz
Now, calculating the possible wavelengths:
λ = 343/ 5259.9 or 343/ 5293.9
λ₂ = 6.48 cm or 6.52 cm
<h3>Why is beat frequency important?</h3>
When two waves with almost identical frequencies traveling in the same direction collide at a certain location, beats are produced. The opposing beneficial and harmful disruption causes the sound to alternatively be loud and weak whenever two sound waves with different frequencies reach your ear. This is referred to as beating.
The entire value of the frequency difference between the two waves is the beat frequency.
The following formula yields the beat frequency:
fb = |f2 − f1|
Learn more about beat frequency here:
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Briefly outline the caloric theory about the nature of heat
Gravitational force between 2 objects . . .
F = G · m₁ · m₂ / D²
-- You said that F = 3.5 x 10²² Newtons.
-- G = the gravitational constant = 6.67 x 10⁻¹¹ N m² / kg²
-- You want to find D .
F = G · m₁ · m₂ / D²
Multiply each side by D² . . . D² · F = G · m₁ · m₂
Divide each side by F . . . D² = G · m₁ · m₂ / F
So finally . . . D = √(G · m₁ · m₂ / F )
D = √(6.67 x 10⁻¹¹ N·m²/kg² · Earth mass · Sun mass / 3.5 x 10²² N)
<em>D = 4.37 x 10⁻¹⁷ · √(Earth mass · Sun mass) </em> meters