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Andru [333]
3 years ago
7

C10H12O4S(s) + O2(g)  CO2(g) + SO2(g) + H2O(g)

Chemistry
1 answer:
ale4655 [162]3 years ago
8 0

Answer: The coefficient for O_2(g) is 12.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

C_{10}H_{12}O_4S(s)+12O_2(g)\rightarrow 10CO_2(g)+SO_2(g)+6H_2O

Thus in the reactants, there are 12 molecules of oxygen in balanced chemical equation. Thus the coefficient for O_2(g) is 12.

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Explanation:

2 is to 5 is your answer

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How much ice at a temperature of -17.5 ∘C must be dropped into the water so that the final temperature of the system will be 31.
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An insulated beaker with negligible mass contains liquid water with a mass of 0.205kg and a temperature of 79.9 °C How much ice at a temperature of −17.5 °C must be dropped into the water so that the final temperature of the system will be 31.0 °C? Take the specific heat for liquid water to be 4190J/Kg.K, the specific heat for ice to be 2100J/Kg.K, and the heat of fusion for water to be 334000J/kg.

The answer to the above question is

Therefore 0.1133 kg  ice at a temperature of -17.5 ∘C must be dropped into the water so that the final temperature of the system will be 31.0 °C

Explanation:

To solve this we proceed by finding the heat reaquired to raise the temperature of the water to 31.0 C from 79.9 C then we use tht to calculate for the mass of ice as follows

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Total heat = mi×L + mi×ci×ΔTi = mi×334000 + mi × 2100 × (0 -−17.5) = 42002.655 J

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3 years ago
How many moles are contained in 3.131 × 1024 particles?
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<u>Given:</u>

The number of particles = 3.131 * 10²⁴

<u>To determine:</u>

The number of moles corresponding to the given particles

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3.131* 10²⁴ particles * 1 moles/6.023 * 10²³ particles = 5.199 moles

Ans: A) 5.199 moles are contained in 3.131* 10²⁴ particles



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