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Olenka [21]
3 years ago
8

Calculate the mass, in grams, of each sample. a. 1.1 * 1023 gold atoms b. 2.82 * 1022 helium atoms c. 1.8 * 1023 lead atoms d. 7

.9 * 1021 uranium atoms
Chemistry
1 answer:
Vlada [557]3 years ago
5 0

Answer:blablablablablabla

Explanation:

Blablabla

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which of the following pairs of elements could react to form an ionic compound? A. potassium and calcium B. sulfur and oxygen C.
Grace [21]
The correct option is FLUORINE AND COPPER.
An ionic compound is usually formed by the combination of a metal and a non metal, the metal usually act as an electron donor while the non metal act as an electron acceptor. Thus, in ionic compounds, there is total transfer of electrons from the metal to the non metal. In the question given here, copper is the metal while the fluorine is the non metal.<span />
4 0
3 years ago
Which type of bond is formed between atoms of solid gold
goldfiish [28.3K]

Answer:

covalent bonds

Explanation:

5 0
3 years ago
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What is the central atom of C2H4Br2
Korvikt [17]

Answer:

1.2,dibromoethane is the sha'awa .

6 0
3 years ago
what volume of hydrogen gas is evolved from a reaction between 0.52 g of Na and water? This gas is collected at 20 C and 745mmHg
guapka [62]
The  volume of  hydrogen  gas  that evolved  is   calculated  as  follows
by  use  of   ideal  gas  equation

that  is  PV = nRT
P=745  mm hg
V= ?
R(gas  constant)= 62.36 L.mm hg/mol.k
T= 20 + 273 = 293 k
n=number  of  moles which is calculated as  follows
find the  moles  of Na  used
= 0.52/23=0.023  moles

write the reacting equation
2Na +2H2O =2NaOH +H2
by  use  of reacting  ratio  between  Na : H2  which  is  2:1  therefore  the mole  of H2 = 0.023/2 =0.0115  moles

by  making  the  volume  the   subject  of  the formula
v=nRT/P
V= (0.0115 x 62.36  x 293) / 745  = 0.283 L


6 0
3 years ago
Determine the poh of a 0.348 m ba(oh)2 solution at 25°c.
vladimir1956 [14]

<u>Given:</u>

Concentration of Ba(OH)2 = 0.348 M

<u>To determine:</u>

pOH of the above solution

<u>Explanation:</u>

Based on the stoichiometry-

1 mole of Ba(OH)2 is composed of 1 mole of Ba2+ ion and 2 moles of OH- ion

Therefore, concentration of OH- ion = 2*0.348 = 0.696 M

pOH = -log[OH-] = - log[0.696] = 0.157

Ans: pOH of 0.348M Ba(OH)2 is 0.157

6 0
3 years ago
Read 2 more answers
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