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Olenka [21]
3 years ago
8

Calculate the mass, in grams, of each sample. a. 1.1 * 1023 gold atoms b. 2.82 * 1022 helium atoms c. 1.8 * 1023 lead atoms d. 7

.9 * 1021 uranium atoms
Chemistry
1 answer:
Vlada [557]3 years ago
5 0

Answer:blablablablablabla

Explanation:

Blablabla

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I need some help pls with science
elena-s [515]

Answer:

the answer to number 9 is A.

Explanation:

6 0
2 years ago
He isotope 62(over28ni has the largest binding energy per nucleon of any isotope. calculate this value from the atomic mass of n
irina [24]
The atomic mass of the isotope Ni ( 62 over 28 ) = 61.928345 amu.
Mass of the electrons: 28 · 5.4584 · 10^(-4 ) amu = 0.0152838 amu ( g/mol )
Mass of the nuclei:
61.928345 amu - 0.0152838 amu = 61.913062 amu (g/mol)
The mass difference between a nucleus and its constituent nucleons is called the mass defect.
For Ni ( 62 over 28 ): Mass of the protons: 28 · 1.00728 amu = 28.20384 amu
Mass of the neutrons: 34 · 1.00866 amu = 34.299444 amu
In total : 62.49828 amu
The mass defect = 62.49828 - 61.913062 = 0.585218 amu
Nucleus binding energy:
E = Δm · c² ( the Einstein relationship )
E = 0.585218 · ( 2.9979 · 10^8 m/s )² · 1 / (6.022 · 10^23) · 1 kg / 1000 g =
= 0.585218 · 8.9874044 · 10 ^16 : (6.022 · 10^23) · 0.001 =
= ( 5.2595908 : 6.022 ) · 0.001 · 10^(-7 ) =
= 0.0008733 · 10^(-7) J = 8.733 · 10^(-11) J
The nucleus binding energy per nucleon:
8.733 · 10^(-11) J : 62 =  0.14085 · 10 ^(-11) =
= 1.4085 · 10^(-12) J per nucleon.
4 0
3 years ago
A second cross was done using a different pair of mice.One parent was a mouse with white fur (bb).The was other parent was a mou
eimsori [14]
Bb, or mostly dominant with a little recessive
3 0
3 years ago
PLEASE HELP ME YOU'LL GET JUST 10 POINTS.
Sphinxa [80]
I want more points for this answer
4 0
2 years ago
A sample of a compound contains 60.0 g C and 5.05 g H. Its molar mass is 78.12 g/mol. What is the compound’s molecular formula
ki77a [65]
The standard atomic weight of a C is 12, and the standard atomic weight of a H is 1.  So to find molar ratio of C and H in the compound: 60.0/12=5, 5.05/1=5. This means the molar ratio of C and H is 5:5, thus 1:1.  Assuming the molecular formula is CnHn, to find molar mass: 12n + 1n = 78.12.  n=78.12/(12+1) = 6.  So the compound's molecular formula is C6H6, benzene.
4 0
3 years ago
Read 2 more answers
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