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Sonja [21]
3 years ago
15

Part A: Explain why and how polar covalent bonds found in water molecules are responsible for waters ability to dissolve many su

bstances, particularly ionic compounds such as salt.
Part B: Identify the solvent and the solute in the solution that has been created in Part A from dissolving salt in water.

Thanks for any help :)

Chemistry
1 answer:
solniwko [45]3 years ago
4 0

Part A -

Water has polar covalent bonds due to the difference in electronegativity between the oxygen and the hydrogen. When a solute such as an ionic compound dissolves, it's constituent ions are pulled apart from one another. Water then forms hydration shells around the pulled apart ions (look above for NaCl being dissolved in water).

This normally only occurs with ionic compounds such as salt and other polar molecules. This is because with non polar molecules, the water would be more strongly attracted to itself meaning it won't form hydration shells.

Part B -

In the example from part A in which an ionic substance is being dissolved in water, the ionic substance is the solute and the water is the solvent.

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melamori03 [73]

Explanation:

In gases the molecules are held together by weak Vander waal forces. Due to this they have more kinetic energy and they tend to diffuse at a faster rate because of more number of collisions between the molecules.

That is why, its molecules readily spread into the atmosphere as compared to the molecules of solids and liquids. Also, when molecules of a gas collide with the walls of a container then they tend to come back at their initial position for a fraction of second or more.

Hence, gas collisions are elastic in nature.

According to Graham's law, rate of diffusion of a gas is inversely proportional to the square root of molar mass of the gas. Hence, more is the molecular weight of gas less likely it is able to diffuse into the surroundings.

       \text{Rate of diffusion} \propto \sqrt{\frac{1}{M}}

Thus, we can conclude that following apply to gases.

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4 0
3 years ago
How many moles of solute would be dissolved in .500 kg of solvent to make a 2.50 molal NaOH solution?
Tom [10]

Molality is a measure of concentration that relates the moles of solute to the kilograms of solvent, it is described by the following equation:

Molality=\frac{molSolute}{kgSolvent}

We are given the molality(2.50m) and kilograms of solvent(0.500kg), so we solve for moles of solute from the equation:

molSolute=Molality\times kgSolvent\begin{gathered} molSolute=2.50m\times0.500kg \\ molSolute=1.25molSolute \end{gathered}

To make a 2.50molal NaOH solution would be needed 1.25moles of solute

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3 0
1 year ago
The rate constant for a certain reaction is k = 5.40×10−3 s−1 . If the initial reactant concentration was 0.100 M, what will the
IceJOKER [234]

Answer : The concentration after 17.0 minutes will be, 4.05\times 10^{-4}M

Explanation :

The expression for first order reaction is:

[C_t]=[C_o]e^{-kt}

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[C_t] = concentration at time 't'  (final) = ?

[C_o] = concentration at time '0' (initial) = 0.100 M

k = rate constant = 5.40\times 10^{-3}s^{-1}

t = time = 17.0 min = 1020 s (1 min = 60 s)

Now put all the given values in the above expression, we get:

[C_t]=(0.100)\times e^{-(5.40\times 10^{-3})\times (1020)}

[C_t]=4.05\times 10^{-4}M

Thus, the concentration after 17.0 minutes will be, 4.05\times 10^{-4}M

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Answer:

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