Answer:
-1.05 V
Explanation:
A detailed diagram of the setup as required in the question is shown in the image attached to this answer. The electrolytes chosen are SnCl2 for the anode half cell and MnCl2 for the cathode half cell. Tin rod and manganese rod are used as the anode and cathode materials respectively. Electrons flow from anode to cathode as indicated. The battery connected to the set up drives this non spontaneous electrolytic process.
Oxidation half equation;
Sn(s) ------> Sn^2+(aq) + 2e
Reduction half equation:
Mn^2+(aq) + 2e ----> Mn(s)
Cell voltage= E°cathode - E°anode
E°cathode= -1.19V
E°anode= -0.14 V
Cell voltage= -1.19 V - (-0.14V)
Cell voltage= -1.05 V
Answer:
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Answer:
Solution A is correct.
Explanation:
Strong acids or bases are assumed to dissociate completely when in a aqueous solution.
Answer:
The order is Hydrogen, Carbon, Sulfur, Iodine
Explanation:
According to the periodic table. The order is Hydrogen, Carbon, Sulfur, Iodine. You can search up an image of a periodic table, it will help you.