Answer:
The extension of the spring is 0.392 m.
Explanation:
Given;
spring constant, k = 50 N/m
mass attached to the spring, m = 2.0 kg
let the extension of the spring = x
The extension of the spring is calculated by applying Hook's law;
F = kx
mg = kx
Therefore, the extension of the spring is 0.392 m.
i have no idea
I don't even know how we are here
Answer:
If they both remain constant they ain't moving, It states that the rate of change of velocity of an object is directly proportional to the force applied and takes place in the direction of the force. It is summarized by the equation
Explanation:
Answer:
2420 J
Explanation:
From the question given above, the following data were obtained:
Force (F) = 22.9 N
Angle (θ) = 35°
Distance (d) = 129 m
Workdone (Wd) =?
The work done can be obtained by using the following formula:
Wd = Fd × Cos θ
Wd = 22.9 × 129 × Cos 35
Wd = 22.9 × 129 × 0.8192
Wd ≈ 2420 J
Thus, the workdone is 2420 J.
