Which of the following are equivalent units?

A 3 Hz wave has a wavelength of 0.4 m. Calculate the speed of the wave (in m/s).

anyanavicka [17]

The speed of the wave with the given frequency and wavelength is 1.2m/s.

Given the data in the question;

Wavelength of the wave; $\lambda = 0.4m$

Frequency; $f = 3Hz = 3s^{-1}$

Speed of the wave; $v = \ ?$

<h3>Wavelength</h3>

Wavelength is the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.

It is expressed as;

$\lambda = \frac{v}{f}$

Where v is velocity/speed and f is frequency.

Now, we can easily get the speed of the wave by substituting our given values into the expression above.

$\lambda = \frac{v}{f} \\\\0.4m = \frac{v}{3s^{-1}}\\ \\v = 0.4m * 3s^{-1}\\\\v = 1.2ms^{-1}\\\\v = 1.2m/s$

Therefore, the speed of the wave with the given frequency and wavelength is 1.2m/s.

Learn more about Speed, Frequency and Wavelength here: brainly.com/question/27120701

8 0

2 years ago

A rubber rod rubbed with fur acquires a charge of -4,8×10(-9)C. What is the charge on the fur? How much mass is transferred to r

mote1985 [20]

1) The charge left on the fur is equal and opposite to the charge transferred to the rod:
$Q=+4.8 \cdot 10^{9} C$
In fact, when the rod is rubbed with the fur, a net charge of $Q=-4.8 \cdot 10^{-9} C$ has been transferred to the rod, leaving it negatively charged. If we assume the fur was initially neutral, this means that we have now an excess of positive charges on the fur, and the amount of this charge must be equal (in magnitude, but with opposite sign) to the charge transferred to the rod.

2) The mass transferred to the rod is equal to the total mass of the electrons transferred to the rod.
The charge transferred to the rod is
$Q=-4.8 \cdot 10^{-9} C$
The charge of 1 electron is
$e=-1.6 \cdot 10^{-19} C$
So the number of electrons transferred is
$N= \frac{Q}{e}= \frac{-4.8 \cdot 10^{-9} C}{-1.6 \cdot 10^{-19} C}=3.0 \cdot 10^{10}$

The mass of 1 electron is $m=9.1 \cdot 10^{-31} kg$ , therefore the total mass transferred to the rod is
$M=Nm=(3 \cdot 10^{10})(9.1 \cdot 10^{-31} kg)=2.73 \cdot 10^{-20} kg$

7 0

3 years ago

Two children of mass 20.0 kg and 30.0 kg sit balanced on a seesaw with the pivot point located at the center of the seesaw. If t

s2008m [1.1K]

Answer:

The distance from the pivot point that the small child will sit in order to maintain the balance is 1.8 m

Explanation:

Given;

mass of the bigger child, M = 30 kg

mass of the smaller child, m = 20 kg

distance between the two children, d = 3 m

This information can be represented diagrammatically;

3m

|<------------------------------------------------>|

----------------------------------------------------------------------------

↓ x Δ 3-x ↓

20kg 30kg

x is the distance from the pivot point that the small child will sit in order to maintain the balance

Take moment about the pivot;

Clockwise moment = anticlockwise moment

30(3-x) = 20x

90 -30x = 20x

90 = 20x + 30x

90 = 50x

x = 90 / 50

x = 1.8 m

Therefore, the distance from the pivot point that the small child will sit in order to maintain the balance is 1.8 m

7 0

3 years ago

What is 34 + (5) × (1.2465) written with the correct number of significant figures?

bonufazy [111]

Answer: 40

Explanation:

= 34 + 5 * 1.2465

= ‭40.2325‬

= 40

The number of significant figures in the answer should be the same as the number with the least number of significant figures that any of the digits in the equation have.

32 has 2 significant figures so the answer has to be 2 significant figures which is 40.

7 0

3 years ago

This is an interaction in which two waves meet, matching crest to crest and trough to trough. The resultant wave will have an am

mart [117]

Answer:

jao es fac esi ylo saa lbes

Explanation:

hkhhhhkl

4 0

3 years ago