When 2 objects of different masses are pushed with the same force which one accelerates the farthest?
1 answer:
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Answer:
The upper limit on the flow rate = 39.46 ft³/hr
Explanation:
Using Ergun Equation to calculate the pressure drop across packed bed;
we have:
where;
L = length of the bed
= viscosity
U = superficial velocity
= void fraction
dp = equivalent spherical diameter of bed material (m)
= liquid density (kg/m³)
However, since U ∝ Q and all parameters are constant ; we can write our equation to be :
ΔP = AQ + BQ²
where;
ΔP = pressure drop
Q = flow rate
Given that:
9.6 = A12 + B12²
Then
12A + 144B = 9.6 -------------- equation (1)
24A + 576B = 24.1 --------------- equation (2)
Using elimination methos; from equation (1); we first multiply it by 2 and then subtract it from equation 2 afterwards ; So
288 B = 4.9
B = 0.017014
From equation (1)
12A + 144B = 9.6
12A + 144(0.017014) = 9.6
12 A = 9.6 - 144(0.017014)
A = 0.5958
Thus;
ΔP = AQ + BQ²
Given that ΔP = 50 psi
Then
50 = 0.5958 Q + 0.017014 Q²
Dividing by the smallest value and then rearranging to a form of quadratic equation; we have;
Q² + 35.02Q - 2938.8 = 0
Solving the quadratic equation and taking consideration of the positive value for the upper limit of the flow rate ;
Q = 39.46 ft³/hr
<h3><u>Given</u> :</h3>
Three identical resistors of resistances 5Ω, 10Ω and 30Ω are connected with a battery of 12V
We have to find current through the each resistor and equivalent resistance of circuit
➝ Equivalent resistance of series connection is given by
- <u>R = R1 + R2 + R3</u>
➝ We know that, Equal current flow through each resistor in series connection.
➝ As per ohm's law, Current flow through a conductor is directly proportional to the applied potential difference.
- <u>V = IR</u>
◈ <u>Equivalent resistance</u> :
⇒ Req = R1 + R2 + R3
⇒ Req = 5 + 10 + 30
⇒ <u>Req = 45Ω</u>
◈ <u>Current flow in circuit</u> :
⇒ V = IReq
⇒ 12 = I × 45
⇒ <u>I = 0.27A</u>
፨ Therefore, 0.27A current will flow through each resistor.