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Readme [11.4K]
3 years ago
13

How do you figure out the electron configuration of an element?

Chemistry
1 answer:
Rus_ich [418]3 years ago
6 0
Writing the Configuration

Starting at the top of the periodic table and moving from left to right across the rows, write the row number, the block letter and how many squares are in each block's section until you get to the desired element. To calculate the electron configuration for phosphorus (P), which is in the third row, p-block, third element in that block, write: 1s2 2s2 2p6 3s2 3p3. Check your work by adding the electron numbers to see if they equal the atomic number of the element; for this example, you would write: 2+2+6+2+3=15, which is the atomic number of phosphorus.

Special Instructions

Because an atom's orbitals sometimes overlap in real life, you must account for that in your configurations. For the d-block, change the row number to one number less than it actually is. For example, the electron configuration for germanium (Ge) is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2. Notice even though you are on row four, it is called "3d" to account for overlap.


Hope i helped you :) Brainliest?
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What electrically neutral atom will have an electron configuration of 1s2 2s2 2p4?
abruzzese [7]

Answer:- oxygen.

Explanations:- The electronic configuration is given and we are asked to figure out the electrically neutral atom that will have the electron configuration, 1s^22s^22p^4 .

The sum of electrons for this electron configuration is 8. If we look at the periodic table then 8 is the atomic number of oxygen.

So, the electrically neutral atom for the given electron configuration is oxygen.

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3 years ago
How many moles are contained in 2.0 L of N2 at standard temperature and pressure.
GuDViN [60]

0.091 moles are contained in 2.0 L of N2 at standard temperature and pressure.

Explanation:

Data given:

volume of the nitrogen gas = 2 litres

Standard temperature = 273 K

Standard pressure = 1 atm

number of moles =?

R (gas constant) = 0.08201 L atm/mole K

Assuming nitrogen to be an ideal gas at STP, we will use Ideal Gas law

PV = nRT

rearranging the  equation to calculate number of moles:

PV = nRT

n = \frac{PV}{RT}

putting the values in the equation:

n = \frac{1X2}{0.08201 X 273}

n = 0.091 moles

0.091 moles of nitrogen gas is contained in a container at STP.

6 0
3 years ago
A 0.4322 g sample of a potassium hydroxide – lithium hydroxide mixture requires 27.10 mL of 0.3565 M HCl for its titration to th
Yuki888 [10]

The mass percent lithium hydroxide in the mixture with potassium hydroxide, calculated from the equivalence point in the titration of HCl with the mixture, is 19.0%.  

The mass percent of lithium hydroxide can be calculated with the following equation:  

\% = \frac{m_{LiOH}}{m_{t}} \times 100    (1)

Where:

m_{t} = m_{KOH} + m_{LiOH} = 0.4322 g   (2)  

We need to find the mass of LiOH.

From the titration, we can find the number of moles of the mixture since the number of moles of the acid is equal to the number of moles of the bases at the equivalence point.    

\eta_{HCl} = \eta_{LiOH} + \eta_{KOH}

0.0271 L*0.3565 \frac{mol}{L} = \eta_{LiOH} + \eta_{KOH}

\eta_{LiOH} + \eta_{KOH} = 9.66 \cdot 10^{-3} \:mol

Since mol = m/M, where M: is the molar mass and m is the mass, we have:

\frac{m_{LiOH}}{M_{LiOH}} + \frac{m_{KOH}}{M_{KOH}} = 9.66 \cdot 10^{-3} \:mol    (3)                                        

Solving equation (2) for m_{KOH} and entering into equation (3), we can find the mass of LiOH:  

\frac{m_{LiOH}}{M_{LiOH}} + \frac{0.4322 - m_{LiOH}}{M_{KOH}} = 9.66 \cdot 10^{-3} \:mol    

\frac{m_{LiOH}}{23.95 g/mol} + \frac{0.4322 g - m_{LiOH}}{56.1056 g/mol} = 9.66 \cdot 10^{-3} \:mol              

Solving for m_{LiOH}, we have:

m_{LiOH} = 0.082 g

Hence, the percent lithium hydroxide is (eq 1):

\% = \frac{0.082 g}{0.4322 g} \times 100 = 19.0 \%  

Therefore, the mass percent lithium hydroxide in the mixture is 19.0%.

Learn more about mass percent here:

  • brainly.com/question/6992535?referrer=searchResults
  • brainly.com/question/5840377?referrer=searchResults

I hope it helps you!                        

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D. 2- youre adding two negative charges to a neutral element
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