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wolverine [178]
2 years ago
14

If f(x) = 2x^2 + 1 and g(x) = x^2 - 7, find (f - g)(x).

Mathematics
2 answers:
zavuch27 [327]2 years ago
6 0
2x squared +1 (-)x squared -7 is
a.) x squared +8
professor190 [17]2 years ago
5 0

The right answer is 3x^2 - 6 or I guess you can saw D for APEX users

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How to solve 1-(-8)- 12/-3
Fudgin [204]

Answer:

ok so the answer is 13

Step-by-step explanation:

to solve you..

PEMDAS

PLEASE EXUSE MY DEAR AUNT SALLY

1-(-8)-12/-3

1-(-8)+4

1+8+4

9+4

13

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HOPE THIS HELPED YA

4 0
2 years ago
Help me with this pls
Rufina [12.5K]

Answer:

b^-6

Step-by-step explanation:

(b^-2) / (b^4) = b^(-2 - 4)

3 0
3 years ago
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Hi! can anyone help me? Question is down in the picture below! 10 points! Thank you!
Bad White [126]

Answer:2

Step-by-step explanation:

I’m not exactly sure bc I’ve never heard a problem like that before but I believe that’s correct.

5 0
2 years ago
The school is 625 meters far from Alex house. It took him 15 minutes to go from home to school, and run back to home in 10 minut
anygoal [31]

It is given in the question that

The school is 625 meters far from Alex house. It took him 15 minutes to go from home to school, and run back to home in 10 minutes.

Total distance is 625 meters and total time taken is

(10+15) minutes=25minutes

Average speed is

\frac{total \ distance \  travelled}{total \ time \ taken}

= \frac{625}{25}meter/minute = 25 meter/minute

5 0
3 years ago
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you place a cup of 200f coffee on a table in a room that is 67f and 10 minutes later it is 195f. approximately how long will it
kompoz [17]
Newton's law of cooling says the rate of change of temperature is proportional to the difference between the object's temperature and the temperature of the environment.

Here, the object starts out at 200 °F, which is 133 °F greater than the environment temperature. 10 minutes later, the object is 195 °F, so is 128 °F greater than the environment. In other words, the temperature difference has decayed by a factor of 128/133 in 10 minutes.

The solution to the differential equation described by Newton's Law of Cooling can be written as the equation
   T(t) = 67 + 133*(128/133)^(t/10)
where T is the object's temperature in °F and t is the time in minutes from when the object was placed in the 67 °F environment.

The equation 
   T(t) = 180
can be solved analytically, but it can be a bit easier to solve it graphically. A graphing calculator shows it takes 42.528 minutes for the temperature of the coffee to reach 180 °F.

7 0
3 years ago
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