The required point-slope form of the equation of the line is y - 5 = -4(x + 1).
Given that, To determine an equation in point-slope form for the line that passes through the point with the given slope. point: (-1, 5) and m=-4.
What is the slope of the line?
The slope of the line is a tangent angle made by line with horizontal. i.e. m =tanx where x in degrees.
Here,
The point-slope of the equation of the line is given by,
y - y₁ = m(x - x₁)
Put the values in the above equation of the line
y - 5 = -4 (x - (-1))
y - 5 = -4 (x + 1)
Thus, the required point-slope form of the equation of the line is y - 5 = -4(x + 1).
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Answer:
374/105.
Step-by-step explanation:
1/3 of 8 * 2/7
= 1/3 * 8 * 2/7
= 8/3 * 2/7
= 16/21.
2/5 of 7
= 2/5 * 7
= 14/5.
Adding 16/21 + 14/5
= 80 / 105 + (14*21) / 105
= 80/105 + 294/105
= 374/105.
(-5, 7) - Quadrant II
(8 1/2, -4) - Quadrant IV
(0,5) - y axis
Step-by-step explanation:
X ·2 = 12x - 15
2x = 12x - 15
2x + (-12x) = (12x - 15) + (-12x)
Result: x = 3/2
To find the mean, aka average, we must add all the values of the table, then divide that sum by the number of values
