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2 years ago

7

Chemical changes involve the breaking and making of chemical bonds. The answer is always

1 answer:

larisa [96]2 years ago

6 0

Answer:

Chemical reactions involve breaking chemical bonds between reactant molecules (particles) and forming new bonds between atoms in product particles (molecules). The number of atoms before and after the chemical change is the same but the number of molecules will change.

Explanation:

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Which element is most reactive sodium,magnesium, or aluminum and why?

ludmilkaskok [199]

Magnesium would be more reactive.

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3 years ago

Felix adds salt to the boiling water, what will he have in the pot?

Pani-rosa [81]

A mixture called a solution, I think.

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2 years ago

What mass of copper is consumed in the reaction with hydrochloric acid if 10.0 g of gas is collected?

brilliants [131]

Answer:

317 g

Explanation:

Cu + 2HCl --> CuCl2 +H2

1 : 2 1 : 1

1 mole of Cu = 63.5 g

1 mole of H2 = 2g

1 mole Cu produces = 1 mole of H2

63.5 g of Cu produces = 2 g of H2

So

10 g of H2 will be produced from = (63.5/2)*10 = 317 g of Copper

4 0

2 years ago

When dissolved sodium hydroxide reacts with hydrogen sulfate, aqueous sodium, sulfate, water, and heat are formed. Write out the

nignag [31]

Answer:

2 NaOH(aq) + H2SO4(aq) ⇒ Na2SO4 (aq) + 2 H2O(l)

Explanation:

4 0

3 years ago

Be sure to answer all parts. Consider the reaction N2(g) + 3H2(g) → 2NH3(g)ΔH o rxn = −92.6 kJ/mol If 4.0 moles of N2 react with

Sphinxa [80]

Answer : The work done is, $1.98\times 10^4J$

Explanation :

The given balanced chemical reaction is:

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

When 4 moles of $N_2$ react with 12 moles of $H_2$ then it gives 8 moles of $NH_3$

First we have to calculate the change in moles of gas.

Moles on reactant side = Moles of $N_2$ + Moles of $H_2$

Moles on reactant side = 4 + 12 = 16 moles

Moles on product side = Moles of $NH_3$

Moles on reactant side = 8 moles

Change in moles of gas = 16 - 8 = 8 moles

Now we have to calculate the change in volume of gas.

Using ideal gas equation:

$PV=nRT$

where,

P = Pressure of gas = 1.0 atm

V = Volume of gas = ?

n = number of moles of gas = 8 mole

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas = $25^oC=273+25=298K$

Putting values in above equation, we get:

$1.0atm\times V=8mole\times (0.0821L.atm/mol.K)\times 298K$

$V=195.7L$

As the number of moles of gas decreased. So, the volume also deceased. Thus, the volume of gas will be, -195.7 L

Now we have to calculate the work done.

Formula used :

$w=-p\Delta V$

where,

w = work done

p = pressure of the gas = 1.0 atm

$\Delta V$ = change in volume = -195.7 L

Now put all the given values in the above formula, we get:

$w=-p\Delta V$

$w=-(1.0atm)\times (-195.7L)$

$w=195.7L.artm=195.7\times 101.3J=19824.41J=1.98\times 10^4J$

conversion used : (1 L.atm = 101.3 J)

Thus, the work done is, $1.98\times 10^4J$

6 0

3 years ago