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4 years ago

A sample of gas A has a molar mass of 4 grams while a sample of gas B has a molar mass of 16 grams. Which statement holds true?

Chemistry

2 answers:

adelina 88 [10]4 years ago

8 0

Answer: The correct statement is gas A effuses faster than gas B.

Explanation:

To know the rate of effusion of gases, we use Graham's law.

Graham's law states that the rate of effusion of a gas is inversely proportional to the square root of the molar mass of gas. The equation that calculates the rate of effusion of a gas is given by:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

As, rate of effusion is inversely related to the molar mass of the gas, so the gas which have less molar mass will effuse faster than the gas which have more molar mass.

Molar mass of gas A = 4 grams

Molar mass of gas B = 16 grams

Putting values in above equation, we get:

$\frac{Rate_{A}}{Rate_{B}}=\sqrt{\frac{M_{B}}{M_{A}}}
$

$\frac{Rate_{A}}{Rate_{B}}=\sqrt{\frac{16}{4}}\\\\\frac{Rate_{A}}{Rate_{B}}=2\\\\Rate_A=2\times Rate_B$

Rate of gas A is 2 times more than rate of Gas B. Hence, the correct statement is gas A effuses faster than gas B.

jeka944 years ago

4 0

I believe the closest possible answer to this question are:Gas A effuses faster than gas B.The molar mass is directly proportional to the rate of effusion.Thank you for your question. Please don't hesitate to ask in Brainly your queries

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Calculate the molar solubility of lead thiocyanate in pure water. The molar solubility is the maximum amount of lead thiocyanate

OLga [1]

Answer:

$Molar solubility(S)=1.71\times10^{-2} mole/litre$

Explanation:

Assume Ksp of $Pb(SCN)_{2}$ = $2\times10^{-5}$ ( it is general value ,i took it because not given in question)

molar solubilty means how much maximum mole of lead thiocynate is dissolved in one litre of solvent.

Ksp=solubility product;

$Pb(SCN)_2= Pb^{2+} +2SCN^-$

Lets molar solubilty of $Pb(SCN)_2$ is S then

$[Pb^{+2}]=S;$

$[SCN^{-1} ]=2S;$

$Ksp =S\times(2S)^{2} =2\times10^{-5}$

$4S^{3}=2\times10^{-5}$

$S=1.71\times10^{-2} mole/litre$

4 0

3 years ago

How many grams would be in 4.45 x 10^23 molecules of N203

SVETLANKA909090 [29]

Answer:

56.24g

Explanation:

To find the mass of N2O3 in 4.45 x 10^23 molecules, it must first be converted to moles by dividing the number of molecules in N2O3 by Avagadro's number (6.02 × 10^23).

number of moles in N2O3 = 4.45 x 10^23 ÷ 6.02 × 10^23

n = 4.45/6.02 × 10^(23 - 23)

n = 0.74 × 10^0

n = 0.74moles.

Using the formula below to find the mass of N2O3;

mole = mass ÷ molar mass

Molar mass of N2O3 = 14(2) + 16(3)

= 28 + 48

= 76g/mol

mass = mole × molar mass

Mass = 0.74 × 76

Mass = 56.24g

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3 years ago

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kolezko [41]

Answer:

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Explanation:

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3 years ago

How many moles of sucroseare in 5.25x1029 sucrosemolecules?[?]x10[?]Enter your answer with the correctnumber of significant figu

kicyunya [14]

To calculate the number of moles we will use Avogadro's number, which relates the number of molecules contained in a mole of any substance, the relationship between moles and molecules is as follows:

$\begin{gathered} \text{Moles of a subtances=Molecules}\times\frac{1mol}{6.02\times10^{23}molecules} \\ \text{Moles of sucrose=}5.25\times10^{29}molecules\times\frac{1mol}{6.02\times10^{23}molecules} \\ \text{Moles of sucrose=}8.72\times10^5mol \end{gathered}$

In the statement we are given the molecules with 3 significant figures, therefore the answer must also have 3 significant figures. So the answer will be: In 5.25x10^29molecules are 8.72x10^5 mol of sucrose

5 0

1 year ago