Answer:
// Program is written in C++
// Comments are used to explain some lines
// Only the required function is written. The main method is excluded.
#include<bits/stdc++.h>
#include<iostream>
using namespace std;
int divSum(int num)
{
// The next line declares the final result of summation of divisors. The variable declared is also
//initialised to 0
int result = 0;
// find all numbers which divide 'num'
for (int i=2; i<=(num/2); i++)
{
// if 'i' is divisor of 'num'
if (num%i==0)
{
if (i==(num/i))
result += i; //add divisor to result
else
result += (i + num/i); //add divisor to result
}
}
cout<<result+1;
}
Answer:
42.50 dB
Explanation:
Determine the minimum voltage gain
amplitude of input signal ( Vi ) = 15 mV
amplitude of output signal ( Vo) = 2 V
Vo = 2 v
therefore ; minimum gain = Vo / Vi = 2 / ( 15 * 10^-3 )
= 133.33
Minimum gain in DB = 20 log ( 133.33 )
= 42.498 ≈ 42.50 dB
Answer: Engine power is the power that an engine can put out. It can be expressed in power units, most commonly kilowatt, pferdestärke (metric horsepower), or horsepower.
Explanation: (I hope this helped!! ^^)
Answer:
Explanation:
B. you would grab the plug closest to the outlet
