Answer:
113.69°k
Explanation:
V1=85L of helium V2=32L
T1= 29°C +273= 302°K T2=?
T2=<u>TIV2</u>
V1
T2=<u>(302)(32)</u>= <u>9664</u>
85 85
T2= 113.69°K
Are produced 72 grams of water in this reaction.
<h3>Mole calculation</h3>
To find the value of moles of a product from the number of moles of a reactant, it is necessary to observe the stoichiometric ratio between them:

Analyzing the reaction, it is possible to see that the stoichiometric ratio is 1:2, so we can perform the following expression:



So, if there are 2 mols of Ca(OH)2:
Ca(OH)2 | H2O


Finally, just find the number of grams of water using your molar mass:


So, 72 grams are produced of water in this reaction.
Learn more about mole calculation in: brainly.com/question/2845237
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Explanation: