Answer:
The specific heat capacity of aluminum is 0.90 j/g.°C.
Explanation:
Given data:
Mass of Al cube = 10 g
Heat absorbed = 677 j
Initial temperature=T1 = 50°C
Final temperature =T2= 125°C
Specific heat of aluminum = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 125°C - 50°C
ΔT = 75°C
Now we will put the values in formula.
Q = m.c. ΔT
677 j = 10 g × c × 75°C
c = 750 g.°C
c = 677 j /750 g.°C
c = 0.90 j/g.°C
The specific heat capacity of aluminum is 0.90 j/g.°C.
