Question

This is edgenuity btw

Answer 1

Answer:

The specific heat capacity of aluminum is 0.90 j/g.°C.

Explanation:

Given data:

Mass of Al cube = 10 g

Heat absorbed = 677 j

Initial temperature=T1 = 50°C

Final temperature =T2= 125°C

Specific heat of aluminum = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 125°C - 50°C

ΔT = 75°C

Now we will put the values in formula.

Q = m.c. ΔT

677 j = 10 g × c ×  75°C

c = 750 g.°C

c = 677 j  /750 g.°C

c = 0.90 j/g.°C

The specific heat capacity of aluminum is 0.90 j/g.°C.