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kozerog [31]
4 years ago
6

What is the tendency of a solute to change the boiling point of a solid called?

Chemistry
2 answers:
Bumek [7]4 years ago
6 0
Boiling point elevation
Ludmilka [50]4 years ago
3 0
Boiling point elevation
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Equation of bhr and h2o
guajiro [1.7K]
HBr + H2O = H3O + Br2
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3 years ago
Scientists recently discovered that firing low-energy particles at potatoes keeps the potatoes
vodomira [7]

Answer:

By allowing the potatoes to be stored longer so they can be sold during winter months.

Explanation:

Since low energy particles are fired at the potatoes to prevent them from developing unwanted sprouts, it means that it prevents sprouts from growing on the potatoes.

Now, winter is wet period which encourages more growth of the sprouts. Thus, the way this development will affect the industry is that the potatoes will be stored for longer period and then sold in the winter.

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3 years ago
7.The _____ theory of matter states that all particles of matter are in constant motion.
SashulF [63]
The kinetic energy theory of matter states that all particles of matter are in constant motion.
Kinetics has to do with some kind of movement, which is why this answer is the only plausible one. 
6 0
4 years ago
Read 2 more answers
8. The standard enthalpy of formation of RbF(s) is –557.7kJ/mol and the standard enthalpy of formation of RbF(aq, 1 m) is –583.8
garri49 [273]

Explanation:

Given

The enthalpy of formation of RbF (s) is –557.7kJ/mol

The standard enthalpy of formation of RbF (aq, 1 m) is –583.8 kJ/mol

The enthalpy of solution of RbF = Enthalpy of RbF (aq) - Enthalpy of formation of RbF (s)

= -583.8 - (-557.7)  kJ/mol

= -26.1 kJ/mol

The enthalpy is negative which means that the temperature will rise when RbF is dissolved.

3 0
3 years ago
A vertical cylindrical tank contains 1.80 mol of an ideal gas under a pressure of 0.300 atm at 20.0°C. The round part of the tan
frez [133]

Answer:

Part A m = 97.37 Kg

Part B H = 4.59 meters

Explanation:

Part A

Pressure is equal to force per unit area

P = \frac{F}{A}

Here force is equal to the weight of the piston

Thus

P = \frac{m*g}{A}

On rearranging the equation, we get -

m = \frac{PA}{g} \\m = \frac{P\pi r^2}{g}

Substituting the given values we get

m = \frac{0.3*1.013*10^5*0.1^2}{9.8} \\m = 97.37

Part B

We know that

V = \pi r^2h\\

On substituting the given values we get -

pV = nRT\\V = \frac{nRT}{p}

V = \frac{1.8*8.314*293}{0.3039*10^5} \\V = 0.1442 m^3

Height

= \frac{V}{\pi r^2} \\= \frac{0.1442}{\pi 0.1^2} \\= 4.59

4 0
3 years ago
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