Answer:
d = 19.92 m
Explanation:
As in this exercise there is friction we must use the relationship between work and energy
W = ΔEm
Look for energy in two points
Initial. Fully compressed spring
Em₀ = 
= ½ k x²
Final. When the block stopped
= 0
Let's look for the work of the rubbing force
W = fr d cos θ
Since rubbing is always contrary to movement, θ = 180
W = - fr d
Let's use Newton's second Law, to find the force of friction
Y Axis
N- w = 0
N = mg
The equation for the force of friction is
fr = μ N
fr = μ mg
We substitute in the work equation
W = - μ m g d
We write the relationship of work and energy
-μ m g d = 0 - ½ k x²
d = ½ k x² / μ m g
Let's calculate
d = ½ 131 2.1 2 / (0.74 2 9.8)
d = 19.92 m
Answer:
α = 2.6 +1.7 t - 0.14 t³
Explanation:
Given that
ω(t) = at + bt² - ct⁴
where a = 2.6 rad/s², b = 0.85 rad/s³ and c = 0.035 rad/s⁵
We know that angular acceleration is the rate of change of angular velocity
α = dω/dt
ω(t) = at + bt² - ct⁴
dω/dt= a + 2 b t - 4 ct³
So
α = a + 2 b t - 4 ct³
By putting the values of a b and c
α = a + 2 b t - 4 ct³
α = 2.6 + 2 x 0.85 t - 4 x 0.035 t³
α = 2.6 +1.7 t - 0.14 t³
Try to draw Humpty Dumty cracked on the floor with men all around him
<span>Mass doesn't change when the temperature
of the ball changes.
(Unless, of course, it gets so hot that it melts,
and part of it falls off
and rolls under the table.)</span>
Explanation: As the angle is increased the acceleration of the object is increased as the angle increases the component of the force parallel to the incline increases and the component of forced perpendicular to the inclined decreases it is the parallel component of the weight vector that causes the acceleration.
