Jill says that 12.6 repeating is less than 12.63. Explain her error.

2 answers:

4 0

12.6 repeating is the equivalent of 12.666666666666 and so on but if you rounded, it would be 12.67. So, compare 12.67 and 12.63. 12.67 is larger.

Elena-2011 [213]4 years ago

3 0

She is wrong because 12.66 is greater than 12.63. The last digit of 12.66 (6) is larger than the last digit of 12.63 (3) Even if 12.6 keeps on going (12.66666.....) 6 will always be bigger than 3.
Hope that helped :)

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A company that makes hair-care products had 5,000 people try a new shampoo. of the 5,000 people, 15 had a mild allergic reaction

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750 people had the allergic reaction. Hope this helps

8 0

3 years ago

Find the area of the shaded region if the dimensions of the unshaded region are 18ft x 22ft . use 3.14 for π as necessary.

aivan3 [116]

The area of the shaded region in the given image is: 1,111.84 ft²

<h3>How to Find the Area of a Shaded Region?</h3>

To find the area of the shaded region in the image given, find the areas of the unshaded region, then subtract it from the total area of the whole figure.

Area of the total figure = area of two semicircles + area of the rectangle.

Dimensions of the rectangle is given as, 18ft x 22ft.

Area of the rectangle = 18ft × 22ft = 396 ft²

The diameter of each of the semicircle = 7 + 7 + 18 = 32 ft

The radius of each of the semicircle = 1/2(32) = 16 ft

Area of the two semicircles = 2(1/2 × πr²) = 2(1/2 × 3.14 × 16²)

Area of the two semicircles = 803.84 ft²

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The total area = 704 + 803.84

The total area = 1,507.84 ft²

The area of the shaded region = 1,507.84 - 396

The area of the shaded region = 1,111.84 ft²

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8 0

2 years ago

This my test question I'm 100 bad at math 2b2+16b+49÷2b+4

krek1111 [17]

2b^2 + 81/2 b + 4

basically 2b^2 + 16b + 49/2 b + 4
= (2b^2) + 16b+49/2b) + (4)
= 2b^2 + 81/2 b + 4

5 0

3 years ago

!!!!! PLEASE HELP ME !!!!!

goblinko [34]

Answer:

The correct option is C : x² + (y +3)² = 9 .

Step-by-step explanation:

We know that the general equation for a circle is ( x - h )² + ( y -k )²= r², Where,

r is the radius.
(h , k) is the center.

Let the point be ( 0 , -y) , since it is on negative y axis . And the circle passes through the origin that is (0,0) . Hence the center will be 3 units down the y - axis that is ( 0 , -3) .Hence h will be 0 and y = (-3) .

Now its given that the radius of the circle is 3. So on substituting r = 3 , in standard form we have ,

⇒ ( x -h )² + ( y - k )²= r²

⇒ ( x - 0)² + { y - (-3) }² = 3²

⇒ x² + ( y + 3) ² = 3²

⇒ x² + ( y + 3)² = 9