Answer:
The transition-metal have the highest oxidation number is Mo in Rb₃[MoO₃F₃]
Explanation:
Transition metals are metals that are found in the middle of the periodic table.
For the compounds:
Rb₃[MoO₃F₃]: Rb is an alkali metal that has a charge of +1. that means [MoO₃F₃] is -3. The oxyfluoride O₃F₃ has a charge of -9. That means the <em>Mo is +6</em>
K₄[Mn(CN)₆]: Potassium is +1, thus, the [Mn(CN)₆] is -4, As the CN is -1 and there are 6, the <em>Mn is +2</em>
Na[Ag(CN)₂]: As Na is +1, the [Ag(CN)₂] is -1. As CN are -1, the <em>Ag is +1</em>
K₂[PtCl₆]: Potassium is +1, the [PtCl₆] is -2, As the Cl are -1, the <em>Pt is +4</em>
[Co(NH₃)₄Cl₂]: The NH₃ are neutral, The Cl are -1, that means the <em>Co is +2.</em>
The transition-metal have the highest oxidation number is<em> Mo +6</em>
I hope it helps!
Answer : The balanced reaction is,
Explanation :
According to the Brønsted-lowry concept, a substance is known as acid if it can donate a proton and as a base if it can accept a proton.
The given substance may be a molecule of an ion. The reaction of an acid with the base constitutes the transfer of a proton from acid to the base.
The balanced reaction will be,
In this reaction, is an acid and is donating a proton to the base and both are the reactants. is the conjugate acid of and is the conjugate base of and are the products.
Hence, the balanced reaction is,
Answer:
C.5
Explanation:
A number of electrons present in valence shell of penultimate Shell represents the group of elements.
For s block elements: no.of group=number of valence shell electron.
p block elements: no. of group= 2 + 10 + number of valence electrons.
d block elements: no. of group= number(n-1)d electrons + number of electrons in nth shell.
Here, the differential electron is in p orbital hence, it belongs to p block
No. of group= 2+ 10 + 3=15 i.e 15th group or VA group.
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