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Anna35 [415]
2 years ago
7

What is the change in enthalpy for the single replacement reaction between solid zinc and Cs2SO4 in solution to produce cesium a

nd ZnSO4? Zn + Cs2SO4 → 2Cs + ZnSO4 Given: `"Cs"_2"SO"_4(aq): DeltaH_f °= –1,400 "kJ"` `"ZnSO"_4(aq): DeltaH_f °= –1,063 "kJ"`
Chemistry
1 answer:
Digiron [165]2 years ago
4 0

The change in enthalpy refers to the amount of heat absorbed or heat evolved in a reaction which is carried out at constant pressure.

The change in enthalpy of a reaction is equal to the sum of formation of products minus sum of formation of reactants. It is denoted by \Delta H.

The given reaction is:

Zn + Cs_{2}SO_{4} \rightarrow 2Cs + ZnSO_{4}

\Delta H = \Delta H_{f}^{0}(products))-\Delta H_{f}^{0}(reactants))

Substitute the given values \Delta H_{f}^{0}(products)  and \Delta H_{f}^{0}(reactants) in above formula, we get

\Delta H = -1,063 kJ -(-1,400 kJ)

= + 337 kJ

Thus, change in enthalpy for the single replacement reaction is + 337 kJ


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