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NikAS [45]
4 years ago
6

How many significants are in 54.0047

Chemistry
1 answer:
erik [133]4 years ago
6 0

Answer:

There are 6

Explanation:

The significant figures in that number are  5 4 0 0 4 7

Hope this helps:)

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How can different forms of energy be classified?
Goryan [66]

There are many forms of energy: like solar, wind, wave and thermal to name a few, but the 6 Forms of Energy we study in Needham are: Sound, Chemical, Radiant, Electric, Atomic and Mechanical. Sound Energy- is produced when an object is made to vibrate. Sound energy travels out as waves in all directions.



3 0
3 years ago
214 Po goes under alpha decay what is the equation?
Katyanochek1 [597]
Alpha decay represents the forceful ejection of two protons and two neutrons from the nucleus of the parent atom. If 214 Po undergoes alpha decay, the equation would be:

214 Po ➡️ 210 Pb + 4 He + energy

Alpha decay is in the form of a helium nucleus, two protons and two neutrons.
5 0
3 years ago
This is my question.............
bazaltina [42]

Answer:

-3.15 °Celsius I think.

8 0
3 years ago
Read 2 more answers
1. How would you use your results to tell the relative ages of the rock layers in a new section of strata?
DanielleElmas [232]

Answer:

The more  worn-out the rock is, the older it is

Explanation:

Hello,

The different layers a rock has could be useful to date it, as long as the deepest layers account for the oldest rocks because they haven been worn out due to erosion and others natural events. Thus, one can say that the more  worn-out the rock is, the older it is when we want to analyze a new section of strata.

Best regards.

8 0
4 years ago
1.45 moles of helium gas occupies a volume 18.5 L at a pressure of .85 atm. What is the temperature of the gas in K and °C?
Anon25 [30]

Answer: The temperature of the gas is 132.25K and -140.75°C

Explanation:

Given that:

Volume of helium gas (V) = 18.5L

Temperature of helium gas (T) = ?

Pressure (P) = 0.85 atm

Number of moles (n) = 1.45 moles

Molar gas constant (R) is a constant with a value of 0.082 atm L K-1 mol-1

Then, apply the formula for ideal gas equation

pV = nRT

0.85atm x 18.5L = 1.45 moles x 0.082 atm L K-1 mol-1 x T

15.725 atm•L = 0.1189 atm•L•K-1 x T

T = 15.725 atm•L / 0.1189 atm•L•K-1

T = 132.25K

Given that temperature in Kelvin is 132.25, convert it to Celsius by subtracting 273

So, T(in Celsius) = 132.25K - 273

= -140.75°C

Thus, the temperature of the gas is 132.25K and -140.75°C

5 0
4 years ago
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