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NikAS [45]
3 years ago
6

How many significants are in 54.0047

Chemistry
1 answer:
erik [133]3 years ago
6 0

Answer:

There are 6

Explanation:

The significant figures in that number are  5 4 0 0 4 7

Hope this helps:)

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Uranium has an atomic weight of 238 amu.
shepuryov [24]

Answer:

U= 238g/mol

U2O5= 556g/mol

Explanation:

Since U= 238

O=16

U3O5= 2(238)+3(16)=556g/mol

4 0
3 years ago
H-1
bonufazy [111]
Answer = B = Neutrons and Mass Number

Isotopes 
are defined as those atoms which have same atomic number but different atomic masses.

Atomic mass is basically the number of protons and neutrons present in an atom.

Atomic number is the number of protons present in an atom.

So, in isotopes the number of protons are same but the number of neutrons vary due to which atomic masses also vary.
In given three isotopes, all have same number of protons but different number of neutrons.
i.e.
H-1 = 1 P + 0 N = 1 u (Proton)
H-2 = 1 P + 1 N = 2 u (Deuterium)
H-3 = 1 P + 2 N = 3 u (Tritium)

Hence, it is clear that the number after H shows a change in number of neutrons and mass number.

7 0
3 years ago
Read 2 more answers
What is the oxidizing agent in galvanic cell?
ipn [44]
The ion in the cathode that gains electrons
7 0
3 years ago
Read the following chemical equation.
elena55 [62]

Answer:

Iron gains three electrons.

5 0
3 years ago
How many grams of CO₂ can be produced from the combustion of 2.76 moles of butane according to this equation: 2 C₄H₁₀(g) + 13 O₂
Vilka [71]

Answer:

485.76 g of CO₂ can be made by this combustion

Explanation:

Combustion reaction:

2 C₄H₁₀(g) + 13 O₂ (g) → 8 CO₂ (g) + 10 H₂O (g)

If we only have the amount of butane, we assume the oxygen is the excess reagent.

Ratio is 2:8. Let's make a rule of three:

2 moles of butane can produce 8 moles of dioxide

Therefore, 2.76 moles of butane must produce (2.76 . 8)/ 2 = 11.04 moles of CO₂

We convert the moles to mass → 11.04 mol . 44g / 1 mol = 485.76 g

5 0
3 years ago
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