Answer:
2.91 grams of Magnesium
Explanation:
I put a picture . I used the molar mass of magnesium which can be calculated from the periodic table or simply google it. :) I hope it helps - Enrique
Answer:c
I need at least 20 characters to post
Answer:
See explanation
Explanation:
Full molecular equation;
2NH3(aq) + AgNO3(aq) -------> [Ag(NH3)2]NO3(aq)
Full ionic equation
2NH3(aq) + Ag^+(aq) + NO3^-(aq) --------> [Ag(NH3)2]^+(aq) + NO3^-(aq)
Net ionic equation;
2NH3(aq) + Ag^+(aq) --------> [Ag(NH3)2]^+(aq)
When Silver nitrate is mixed with a solution of aqueous ammonia, a white and cloudy solution was observed.
<span>To solve this we need to balance the equations first.
So Hg + S --> HgS is balanced
One mole of Hg requires one mole of S to form one mole of HgS.
Number of moles of Sulphur = mass/ molar mass = 157/32 = 4.906
So 4.90 moles of S reacts with 4.90 moles of Hg.
Hence there are 4.90 moles of 4.90 of Hg.
Mass = number of moles * molar mass of Hg
Mass = 4.906 * 200.59 = 982.891g</span>
The relative molecular mass of the gas : 64 g/mol
<h3>Further explanation</h3>
Given
Helium rate = 4x an unknown gas
Required
The relative molecular mass of the gas
Solution
Graham's Law
r₁=4 x r₂
r₁ = Helium rate
r₂ = unknown gas rate
M₁= relative molecular mass of Helium = 4 g/mol
M₂ = relative molecular mass of the gas
Input the value :
