Question

Identify the double displacement reaction. 3Pb 2h 3PO 4 ⟶ 3H 2 Pb 3(PO 4) 2 2NO 2 ⟶ 2O 2 N 2 2NaBr Ca(OH) 2 ⟶ CaBr 2 2NaOH 2NH 3 H 2SO 4 ⟶ (NH 4) 2SO 4.

Answer 1

Reaction 3 is the double displacement reaction.

Double displacement reaction occurs when the negatively and the positively charged ions of the compounds interchange their position when the new compound in the product is formed.

Which is a double displacement reaction?

In the first reaction, the element lead (Pb) is not an ion and no exchange of the cations or the anions occurs hence it is not a double displacement reaction.

In the second reaction, one compound is getting split into two new compounds and is a decomposition reaction.

In the third reaction,  $\rm Br^{-}$ in $\rm 2NaBr$ and $\rm (OH)_{2}$ in $\rm Ca(OH)_{2}$ are anions and cations and exchanges their places to produce two new compounds  $\rm CaBr_{2} + 2NaOH.$

In the fourth reaction, a single compound is generated as the result of the combination reaction and hence, it is not the double displacement reaction.

Therefore, $\rm 2NaBr + Ca(OH)_{2} \rightarrow CaBr_{2} + 2NaOH$ is the double displacement reaction.

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