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KIM [24]
2 years ago
12

What happens to carbon dioxide?

Chemistry
2 answers:
oksian1 [2.3K]2 years ago
5 0
Carbon moves from the atmosphere to the oceans.
Molodets [167]2 years ago
3 0
Moves from the atmosphere to the oceans
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Compounds can be broken down into what two types of substances?
KatRina [158]
Chemical and physical
6 0
3 years ago
Silver can be electroplated at the cathode of an electrolysis cell by the half-reaction. Ag+(aq)+e−→Ag(s) Part A Silver can be e
dmitriy555 [2]

Answer: Mass of silver deposited at the cathode is 37.1g

Explanation: According to Faraday Law of Electrolysis, the mass of substance deposited at the electrode (cathode or anode) is directly proportional to quantity of electricity passed through the electrolyte

Faraday has found that to liberate one gm eq. of substance from an electrolyte, 96500C of electricity is required.

Ag^+ +e− ==> Ag(s)

Given that

Current (I) = 8.5A

Time (t) = 65 *60 = 3900s

Quantity of electricity passed = 8.5*3900 =33150C

Molar mass of Ag= 108g

96500C will liberate 108g

33150C will liberate Xg

Xg= (108*33150)/96500

=37.1g

Therefore the mass of Ag deposited at the cathode is 37.1g.

3 0
3 years ago
The pH of a Ba(OH) 2 solution is 10.00. What is the H+ ion concentration of this solution?
I am Lyosha [343]

Answer:

Option D. 1×10¯¹⁰ M

Explanation:

From the question given above, the following data were obtained:

pH = 10

Hydrogen ion concentration, [H+] =?

The hydrogen ion concentration, [H+] of the Ba(OH)2 solution can be obtained as follow:

pH = – Log [H+]

pH = 10

10 = – Log [H+]

Divide both side by – 1

– 10 = Log [H+]

Take the antilog of – 10

[H+] = antilog (– 10)

[H+] = 1×10¯¹⁰ M

Therefore, the hydrogen ion concentration, [H+] of the Ba(OH)2 solution is 1×10¯¹⁰ M

7 0
3 years ago
Lithium forms compounds which are used in dry cells and storage batteries and in high-temperature lubricants. It has two natural
agasfer [191]

The naturally occurring isotopes of Li are Li-6 of mass 6.015121 amu and Li-7 of mass 7.016003 amu. The atomic mass of Li is 6.9409 amu, the percent abundance can be calculated using the following relation.

Atomic mass=m(Li-6 )×%(Li-6 )+m(Li-7 )×%(Li-7 )

Let the percent abundance of Li-6 be X thus, that of Li-7 will be 1-X, putting the values,

6.9409 amu=6.015121 amu\times X+7.016003 amu(1-X)

Or,

6.9409 =6.015121 X+7.016003-7.016003 X

Or,

X=0.075

Thus, 1-X=1-0.075=0.925

Thus, percent abundance of Li-6 is 0.075 or 7.5 % and that of Li-7 is 0.925 or 92.5%.

5 0
3 years ago
Read 2 more answers
If it takes 87.0 min for the concentration of a reactant to drop to 20.0% of its initial value in a first-order reaction, what i
charle [14.2K]

Answer:

0.0185 min⁻¹

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

20.0 % of the initial values is left which means that 0.20 of [A_0] is left. So,

\frac {[A_t]}{[A_0]} = 0.20

t = 87.0 min

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.20=e^{-k\times 87.0}

<u>k = 0.0185 min⁻¹</u>

4 0
4 years ago
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