An aqueous solution is tested with an electrical conductivity probe.The conductivity probe does not detect an electric current .
2 answers:
Answer:
Sulphur (IV) Oxide solution
Explanation:
Sulphur (IV) Oxide with the chemical symbol is a covalent compound consisting only of nonmetals. In chemistry it is well known that Covalent compounds do not conduct electricity because they have no free electrons and ions.
Answer:
Solutions i.e Sulphur (IV) Oxide solution
Explanation:
SULFUR (IV) OXIDE is a gas with a toxic smell like burnt matches, and turn moist litmus pink. It can be manufactured as by product of copper extraction.
CONDUCTIVITY refers to measurement of ability of solutions or substance to conduct electricity.
CONDUCTIVITY PROBES ; Is used to measure ectrical conductivity in solutions and can be used to determine the total ion concentration of aqueous solution.
The conductivity probes does not detect electric current with SULPHUR (IV) OXIDE solution because charge cannot move through it when the coductivity probe was used to carry out test on it.
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There are 1.2 hr would this current have to be applied to plate out 7. 20 g of iron .
Calculation ,
Given ; Current ( I ) = 5. 68 A
In , the valancy of Fe is +2 .
2 moles of are required for the decomposition of 1 mole of Fe .
7. 20 g of Fe in moles = 7. 20 g /55.845 g/mol =0.12 mole
x moles of are required for the decomposition of 0.128 mole of Fe .
moles of are required = 0.256 moles
Charge on 1 mole of = 96500 C
Charge on 0.256 mole of = 24704 C
Current ( I )= Q/t
t =Q / I = 24704 C/5. 68 A = 4349 sec = 1.2 hr
Therefore , there are 1.2 hr would this current have to be applied to plate out 7. 20 g of iron .
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