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DENIUS [597]
3 years ago
6

Arrhenius base definition

Chemistry
1 answer:
kompoz [17]3 years ago
6 0

Arrhenius base is a substance that , when dissolved in an aqueous solution , increase the concentration of hydroxide (OH) ion in the solution


I hope that's help !

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What is the mass number of an isotope with an atomic number of 57 and that has 69 neutrons?
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Answer:

mass number=126

Explanation:

57+69=126

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The process by which the energy of sunlight is converted into the energy of glucose
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Photosynthesis. Easy ;) have a nice day

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explain how a metal with one valence electron compares with a metal with more than one valence electron
slamgirl [31]

Explanation:

A metal with one valence electron is highly reactive compared to those with more than one electron.

Atoms including those of metals reacts in order attain a stable electronic configuration just like those of noble gases.

An atom with one valence electron have just one electron in its valence shell.

  • Metals generally have large sizes.
  • when the electron in this shell is lost, the metal atom can then attain stability.
  • therefore, such atom will quickly want to combine with any other willing to accept the electron so that they can be stable.
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3 years ago
describe the placement of the crucible lid on the crucible when heating the magnesium. Why is it important that this be done cor
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7 0
4 years ago
(06.03 MC) A 50.0 mL sample of gas at 20.0 atm of pressure is compressed to 40.0 atm of pressure at constant temperature. What i
oee [108]

Answer:

New volume is 25.0 mL

Explanation:

Let's assume the gas sample behaves ideally.

According to combined gas law for an ideal gas-

                         \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

where, P_{1} and P_{2} represent initial and final pressure respectively

V_{1} and V_{2} represent initial and final volume respectively

T_{1} and T_{2} represent initial and final temperature (in kelvin) respectively

Here, T_{1}=T_{2}, V_{1}=50.0mL, P_{1}=20.0atm and P_{2}=40.0atm

So, V_{2}=\frac{P_{1}V_{1}T_{2}}{P_{2}T_{1}}=\frac{(20.0atm)\times (50.0mL)}{40.0mL}=25.0mL

So, the new volume is 25.0 mL

6 0
3 years ago
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