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Lorico [155]
4 years ago
11

A measurement has two parts a number and a

Chemistry
1 answer:
givi [52]4 years ago
5 0

Answer:perimiter

Explanation:

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Which one of the following Acids is most likely to hurt you? Acid A: 1.0 M; Acid B: 0.0001M
vaieri [72.5K]
Acid A, assuming the two acids have the same pH. The M stands for molarity which is how concentrated a substance is (basically the higher the molarity the more concentrated the acid is). However, pH refers to how acidic a substance is. If the two acids have different levels of acidity, the answer may be different.
7 0
3 years ago
The carbon-carbon double bond in ethene is ________ and ________ than the carbon-carbon triple bond in ethyne.
lbvjy [14]

Answer:

weaker and longer

Explanation:

Since there are 3 bonds in ethyne in comparision with the 2 bonds of ethyne between carbon atoms, they are attracted more to each other → the bond gets shorter . And since there are one more bond that supports the union → the bond gets stronger

thus the carbon-carbon double bond in ethene is weaker and longer than the carbon-carbon triple bond in ethyne

3 0
3 years ago
Which energy change occurs during boiling?
neonofarm [45]
Heat energy is absorbed by the substance.
4 0
3 years ago
Read 2 more answers
In the haber process, ammonia is synthesized from nitrogen and hydrogen: n2 (g) + 3h2 (g) → 2nh3 (g) δg° at 298 k for this react
allsm [11]

Answer:

e- 7.25 x 10³.

Explanation:

∵ ΔG = -RTlnK,

where, ΔG is the free energy change.

R is the general gas constant (R = 8.324 J/mol.K).

K is the equilibrium constant of the reaction.

  • For the reaction: <em>N₂(g) + 3H₂(g) → 2NH₃(g),</em>

K = (PNH₃)²/(PN₂)(PH₂)³ = (0.65)²/(1.9)(1.6)³ = 5.43 x 10⁻².

∵ ΔG = -RTlnK.

∴ ΔG = -(8.314 J/mol.K)(298 K) ln(5.43 x 10⁻²) = 7.218 x 10³ J/mol.

3 0
3 years ago
The enthalpy of vaporization (ΔH°vap) of benzene is 30.7 kJ/mol at its normal boiling point of 353.3 K. What is ΔS°vap at this t
vazorg [7]

<u>Answer:</u> The correct answer is Option c.

<u>Explanation:</u>

Vaporization is defined as the physical process in which liquid particles get converted to gaseous particles.

Liquid\rightleftharpoons Gas

The value of standard Gibbs free energy is 0 for equilibrium reactions.

To calculate \Delta S^o_{vap} for the reaction, we use the equation:

\Delta S^o_{vap}=\frac{\Delta H^o_{vap}}{T}

where,

\Delta S^o_{vap} = standard entropy change of vaporization

\Delta H^o_{vap} = standard enthalpy change of vaporization = 30.7 kJ/mol = 30700 J/mol    (Conversion factor: 1 kJ = 1000 J)

T = temperature of the reaction = 353.3 K

Putting values in above equation, we get:

\Delta S^o_{vap}=\frac{30700J/mol}{353.3K}=86.9J/(mol.K)

Hence, the correct answer is Option c.

8 0
3 years ago
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