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Lorico [155]
4 years ago
11

A measurement has two parts a number and a

Chemistry
1 answer:
givi [52]4 years ago
5 0

Answer:perimiter

Explanation:

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What are 4 enzymes responsible for digestion along with their substrate and end product​
elena55 [62]

Answer:

4 enzymes responsible for digestion:

1. Salivary amylase ---- substrate: Starch ---- end-product: Maltose  

2. Lipase  ---- substrate: Lipids (fats and oils) ---- end-product: Fatty acids and glycerol

3. Maltase ---- substrate: Maltose ---- end-product: Glucose

4. Protease ---- substrate: Protein ---- end-product: Amino acids

4 0
3 years ago
4. Define power and explain how to determine power.
Ratling [72]
The rate of doing work is called power of an object.
It is also defined as the work done by an object per unit time. Mathematically, its formula is given by :
, W is work done and t is time taken.
The SI unit of power is watts and its commercial unit is kWh.
1 watt = J/s or N-m/s.
5 0
3 years ago
2. When two oppositely charged particles are brought near each other, they produce a torceted the stone
Svetach [21]

Answer:

A

Explanation:

An unbalanced force is your answer.

8 0
3 years ago
If 3 moles of H2 react with two moles of o2 what is limiting reactant
Dominik [7]

H₂ is the limiting reactant.

<u>Explanation:</u>

H₂  reacts with O₂

The reaction would be

2H₂ + O₂ → 2H₂O

According to the balanced equation, 2 moles of H₂ reacts with 1 mole of O₂ to form 2 moles of H₂O.

The ratio of usage of H₂ and O₂ is 2 : 1 respectively

If 3 moles of H₂ and 2 moles of O₂ are present then:

3 moles of H₂ would require 1.5 moles of O₂                 ( 2 : 1 of H₂ and O₂ )

Out of 2 moles of O₂, 1.5 moles would be used and 0.5 mole would be in excess.

Therefore, H₂ is the limiting reactant as the number of moles of H₂ are not enough to use all the O₂.

8 0
4 years ago
Consider the following data. NO2(g) equilibrium reaction arrow identifying the requirement for light NO(g) + O(g) K = 6.8 ✕ 10-4
LenKa [72]

Answer:

K=3.9*10^{-82}

Explanation:

Reactions:

NO_2 (g) \longleftrightarrow NO (g) +O (g)

With: K_1=\frac{[NO][O]}{[NO_2]}=6.8*10^{-49}

O_3 (g) + NO (g) \longleftrightarrow NO_2 (g) + O_2 (g)

With: K_2=\frac{[NO_2}{[O_3][NO]}=5.8*10^{-34}

To achive the reaction we combine those two reactions:

NO_2 (g) + O_3 (g) + NO (g) \longleftrightarrow NO (g) + O (g) + NO_2 (g)

O_3 (g) \longleftrightarrow O (g) + O_2 (g)

The equilibrium constant:

K= K_1*K_2=(6.8*10^{-49})*(5.8*10^{-34})=3.9*10^{-82}

3 0
3 years ago
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