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Aleksandr-060686 [28]
3 years ago
8

The Learning Center charges a one-time fee of $26 plus $10 per piano lesson. Guitar lessons have a one-time fee of $36 plus $8 f

or each lesson. After how many lessons will the cost of learning to play piano be the same or more than learning to play guitar
Mathematics
1 answer:
Aleksandr [31]3 years ago
6 0

Given :

The Learning Center charges a one-time fee of $26 plus $10 per piano lesson.

Guitar lessons have a one-time fee of $36 plus $8 for each lesson.

To Find :

After how many lessons will the cost of learning to play piano be the same or more than learning to play guitar.

Solution :

Mathematical expression of piano lesson :

P_1=26+10x

Mathematical expression of guitar lesson :

P_2=36+8y

( Here, x and y are number of lessons )

Let, after t hours cost of learning to play piano be the same or more than learning to play guitar.

Now, given constraint :

P_1 \geq P_2\\\\26+10t \geq 36+8t\\\\2t \geq  10\\\\t\geq 5

Hence, this is the required solution.

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Find the rate of change between 1980 and 1989
d for P₁ = 80 - 60
d for P₁ = 20

d for P₂ = 76 - 82
d for P₂ = -6

The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.

PART B:
Find the rate of change between 1989 and 1996
d for P₁ = 100 - 80
d for P₁ = 20

d for P₂ = 70 - 76
d for P₂ = -6

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PART C:
Find the rate of change between 1980 and 1996
d for P₁ = 100 - 60
d for P₁ = 40

d for P₂ = 70 - 82
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The rate of change in P₁ is 40 hundred per year. The rate of change in P₂ is -12 hundred per year.
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3 years ago
The larger of two consecutive odd integers is three times the smaller. What is their sum?
Darya [45]
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Answer:

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Step-by-step explanation:

First you have the fraction of 3/12 and need to turn it into a decimal. So to do that you divide 3 by 12 = 0.25. So your percent is 25%

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