Answer:
:)
Explanation:
If we subtract the atomic number from the atomic mass: atomic mass - atomic number = number of protons + number of neutrons - number of protons. Thus we get the number of neutrons present in an atom when we subtract the atomic number from the atomic mass.
<span>The balanced equation would be 4NH3 + 7O2 --> 4NO2 + 6H2O.
Mass of Ammonia = 43.9 g; Molecular weight of Ammonia NH3 = 17.03056 g/mol.
Mass of Oxygen = 258 g; Molecular weight of Oxygen O2 = 31.998 g/mol.
Calculating the moles of Ammonia NH3 = Mass / Molecular weight of ammonia
= 43.9 g / 17.03 g/mol = 2.578 moles of Ammonia.
Calculating the moles of Oxygen O2 = Mass / Molecular weight of Oxygen
=258 g / 31.998 g/mol = 8.063 moles of Oxygen.
2.578 moles of Ammonia will react with (7/4) x 2.578 moles of Oxygen (from the equation) that is 4.5115 moles of O2 to produce the NO2. Since we have more moles of O2 8.063 moles, Ammonia will be the limiting agent.
Calculating the NO2 produces using the coordinate from the equation
Molecular weight of NO2 = 46.00558 g/mol
Mass of NO2 = (2.578 mol) x (4 mol of NO2 / 4 mol of NH3) x (46.006 g /mol)
Produced NO2 = 118.6 g NO2</span>
These are ribosomes definately
That would be 42270 milliliters.
