This is a question in Seneca, plz help asap bc I can't skip it!!
1 answer:
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Explanation:
(a) The given data is as follows.
Pressure on top () = 140 bar =
(as 1 bar =
)
Temperature = = (15 + 273) K = 288 K
Density of gas =
= 0.4548
=
=
Hence, pressure at the natural gas-oil interface is .
(b) At the bottom of the tank,
= 2.206 \times 10^{7} Pa + 700 \times 9.81 \times (6000 - 4700)[/tex]
=
= 309.8 bar
Hence, at the bottom of the well at pressure is 309.8 bar.