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atroni [7]
3 years ago
11

The half-life of carbon-14 is 5,730. What fraction of carbon-14 would remain after 11, 460 years?

Physics
1 answer:
erastovalidia [21]3 years ago
5 0

Answer:

1/4

Explanation:

1/2 of the carbon is left after 5730 years

1/2 of 1/2 is left after another 5730 years

3/4 is decayed

you are left with 1/4

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A dielectric-filled parallel-plate capacitor has plate area A = 30.0 cm2 , plate separation d = 9.00 mm and dielectric constant
PIT_PIT [208]

Answer:

9.96\cdot 10^{-10}J

Explanation:

The capacitance of the parallel-plate capacitor is given by

C=\epsilon_0 k \frac{A}{d}

where

ϵ0 = 8.85x10-12 C2/N.m2 is the vacuum permittivity

k = 3.00 is the dielectric constant

A=30.0 cm^2 = 30.0\cdot 10^{-4}m^2 is the area of the plates

d = 9.00 mm = 0.009 m is the separation between the plates

Substituting,

C=(8.85\cdot 10^{-12}F/m)(3.00 ) \frac{30.0\cdot 10^{-4} m^2}{0.009 m}=8.85\cdot 10^{-12} F

Now we can calculate the energy of the capacitor, given by:

U=\frac{1}{2}CV^2

where

C is the capacitance

V = 15.0 V is the potential difference

Substituting,

U=\frac{1}{2}(8.85\cdot 10^{-12}F)(15.0 V)^2=9.96\cdot 10^{-10}J

4 0
3 years ago
What is the orbit period of the Hubble space telescope
Marina86 [1]

Answer:

95 minutes

Explanation:

The Hubble Space Telescope makes one orbit around Earth every 95 minutes. The electromagnetic spectrum shows that visible light is between infrared radiation and ultraviolet radiation. NASA.gov

7 0
3 years ago
To control whether an object is solid or incorporeal (things can pass through it) you would use the:
Zarrin [17]

Answer:

Gamma radiation or Cathode rays

Explanation:

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5 0
3 years ago
Which one of the following formulas is used to find the voltage of a circuit? 
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D , since Voltage is one joule per coulomb
8 0
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mr Goodwill [35]

Answer:

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