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stiv31 [10]
3 years ago
9

Object a has a mass of 20 g

Physics
1 answer:
Anarel [89]3 years ago
7 0
And.. where is the rest of the question?
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A series RLC circuit has a resistance of 28 Ω and an impedance of 105 Ω. If the rms voltage applied to the circuit is 140 V, wha
sergiy2304 [10]

Answer:49.8W

Explanation:

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3 years ago
Why is weight considered a force
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Because if weight is being applied to an object, the object will have some sort of effect to counter react due to the weights primary objective.
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4 years ago
The hour, minute, and second hands on a clock are 0.25 m , 0.31 m , and 0.34 m long, respectively.
sp2606 [1]

In 1 hour, the hour hand sweeps across 1/12 of the clock's face. In 40 min, the hour hand travels (40 min)/(60 min) = 2/3 of the path it covers in an hour, so a total of 1/12 × 2/3 = 1/18 of the clock's face. This hand traces out a circle with radius 0.25 m, so in 40 min its tip traces out 1/18 of this circle's radius, or

1/18 × 2<em>π</em> (0.25 m) ≈ 0.087 m

The minute hand traverses (40 min)/(60 min) = 2/3 of the clock's face, so it traces out 2/3 of the circumference of a circle with radius 0.31 m:

2/3 × 2<em>π</em> (0.31 m) ≈ 1.3 m

The second hand completes 1 revolution each minute, so in 40 min it would fully trace the circumference of a circle with radius 0.34 m a total of 40 times, so it covers a distance of

40 × 2<em>π</em> (0.34 m) ≈ 85 m

6 0
3 years ago
Which square (A, B, C, or D) represents the repeating subunit of the polymer shown?
Yuri [45]
It would be C my dude.
9 0
3 years ago
Read 2 more answers
In an alcohol-in-glass thermometer, the alcohol column has length 12.66 cm at 0.0 ∘C and length 22.49 cm at 100.0 ∘C. Part A Wha
anygoal [31]

Answer:

62.1566632757\ ^{\circ}C

15.9715157681\ ^{\circ}C

Explanation:

\Delta T = Change in termperature

\Delta L = Change in length

We have the relation

\dfrac{\Delta L}{\Delta T}=\dfrac{22.49-12.66}{100-0}=\dfrac{18.77-12.66}{t-0}\\\Rightarrow t=\dfrac{18.77-12.66}{0.0983}\\\Rightarrow t=62.1566632757\ ^{\circ}C

The temperature is 62.1566632757\ ^{\circ}C

\dfrac{\Delta L}{\Delta T}=\dfrac{22.49-12.66}{100-0}=\dfrac{14.23-12.66}{t-0}\\\Rightarrow t=\dfrac{14.23-12.66}{0.0983}\\\Rightarrow t=15.9715157681\ ^{\circ}C

The temperature is 15.9715157681\ ^{\circ}C

8 0
3 years ago
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