We are given with
x1 = 20 min
s1 = 2 min
x2 = 30 min
s2 = 4 min
p = 0.9
Condition (x > 25)
We need to get the t-value between the two means and comparing it wit the t-value for the time of 25 minutes given that there is a 90% probability that the weather will be good. Simply use the t-test formula and use the t-test table to get the probability.
Answer:
(x - 5)^2 + y^2 = 225/4,
or you could write it as (x - 5)^2 + y^2 = 56.25.
Step-by-step explanation:
The factor form is
(x - h)^2 + (y - k)^2 = r^2 where the center is (h, k) and r = the radius.
So we have:
(x - 5)^2 + (y - 0)^2 = r^2
As the point (-1, 9/2) is on the line:
(-1 - 5)^2 + (9/2)^2 = r^2
r^2 = 36 + 81/4
r^2 = 225/4.
So substituting for r^2:
(x - 5)^2 + (y - 0)^2 = 225/4
(x - 5)^2 + y^2 = 225/4 is the standard form.
Hello,
Answer A
d :the distance in miles
t: the time in hours
v: the speed in miles/hours (vistesse)
d=v*t
==>d=40*4=160(mi)
d=55*x=160==>x=160/55=2.909090... (mi/(mi/h)=h)≈2.91(hours)
3 blocks east and 2 blocks north should be the correct answer :)
Answer:
(x-2)^2-11
Step-by-step explanation:
