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3 years ago

Question 1

Physics

1 answer:

kakasveta [241]3 years ago

3 0

Answer:

W = 600 J

Explanation:

We have,

According to attached figure,

Height of the inclined plane is 60 m

Force acting on the block is 10 N

It is required to find the work must be done against gravity to move it to the top of the incline. The work done is given by :

W = mgh

$W=F\times h\\\\W=10\times 60\\\\W=600\ J$

So, the work done against the gravity is 600 J.

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Auniform thin film of n=1.33 is on top of glass (n=1.5). When monochromatic light with tunable wavelength is directed from above

Aleonysh [2.5K]

Answer:

Explanation:

There is reflection ( two times ) from upper and lower surface of the film . In both cases , reflection is from low to high density medium so there is change in phase of 180 twice .

So for constructive interference

2μd = n λ₁ , d is thickness required , λ is wavelength n₁ is order of bright fringe

For destructive interference ( minimum light )

2μd = (2n+1) λ₂/2

n λ₁ =(2n+1) λ₂/2

(2n+1) / 2n = λ₁ / λ₂

= 650 / 505

= 5 / 4 ( approx )

2n = 4

n = 2

2μd = n λ₁

2 x 1.33 x d = 2 x 650 nm

d = 488.72 nm

5 0

3 years ago

How did the temperature structure of the solar nebula determine planetary composition?

STALIN [3.7K]

Explanation:

The temperature of the solar nebula was decreasing as it moved away from its center. Therefore, only heavy elements could condense in the inner solar system and terrestrial planets could not form with light elements, such as gases. In the outer solar system, the Jovian planets formed mostly with gases, since temperatures were too low to allow rocky compositions.

3 0

3 years ago

(a) Calculate the self-inductance of a solenoid that is

adell [148]

Answer:

a) 0.142mH

b) 14mV

Explanation:

the complete answer is:

(a) Calculate the self-inductance of a solenoid that is <ghtly wound with wire of diameter 0.10 cm, has a cross-sec<onal area of 0.90 cm2 , and is 40 cm long. (b) If the current through the solenoid decreases uniformly from 10 to 0 A in 0.10 s, what is the emf induced between the ends of the solenoid

a) the self inductance of a solenoid is given by:

$L=\frac{\mu_o N^2 A}{L}$

μo: magnetic permeability of vacuum = 4\pi*10^{-7}N/A^2

A: cross sectional area = 0.9cm^2=9*10^{-5}m

L: length of the solenoid = 40cm = 0.4m

The N turns of the wire is calculated by using the diameter of the wire:

N = (40cm)/(0.10cm)=400

By replacing in the formula you obtain:

$L=\frac{(4\pi *10^{-7}N/A^2)(400)^2(9*10^{-5}m^2))}{(0.4m)}=1.42*10^{-4}H$

the self inductance is 1.42*10^{-4}H = 0.142mH

b) to find the emf you can use:

$emf=L\frac{\Delta I}{\Delta t}=(1.42*10^{-4}H)\frac{10A-0A}{0.10s}=0.014V=14mV$

the emf induced is 14mV

4 0

3 years ago

A star with a parallax angle of 0.39" (arcsecond) is what distance away? Give your answer in units of parsecs.

postnew [5]

Answer:

2.56 parsec

Explanation:

Parallax angle is the angle subtended by Earth over a gap of 6 months in its orbital path around the Sun with respect to a star. It can be used to measure the distance to the star.

$d (parsec)=\frac{1}{p (arcsecond)}$

Given: p = 0.39"

Substitute the value:

$d =\frac{1}{0.39"}=2.56$ parsec

5 0

3 years ago

The potential at a point is 20 V. The work done to bring a charge of 0.5 C from infinity to this point will be what?

yulyashka [42]

1. The problem statement, all variables and given/known data The potential at a point is 20 V. Calculate the work done in bringing a charge of 0.5 C to this point. 2. Relevant equations V = Ee / q W = -Ee 3. The attempt at a solution Ee = 10

8 0

3 years ago