A positively charged sphere with a charge of the of 8Q is separated from a negatively charged sphere - 2Q by a distance r. The s
1 answer:
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Answer:
(a)
(b)
Explanation:
(a) Since a constant external force is applied to the body, it is under an uniformly accelerated motion. Using the following kinematic equation, we calculate the final velocity of the mass if it is initially at rest():
According to Newton's second law:
Replacing (2) in (1):
(b) In this case we have . So, we use the final velocity equation:
Answer:
1) a = 6.14 km
2) b = 4.69 km
Explanation:
Let the first building be A, second building be B and third building be C.
Now, bearing of A = 4.76 km in a direction 37° north of east
Bearing of B = 69° west of north
Bearing of C = 28° east of south
Thus if this 3 points form a triangle, we will have the following angles;
Angle at point A = 28 + (90 - 37) = 81°
Angle at point B = 28 + (90 - 69) = 49°
Angle at point C = 180 - (81 + 49) = 50°
Now, the distance between second and third building is "a" which is represented by BC in the triangle attached while the given distance of 4.76 represents side AB. Thus;
Using sine rule, we can find "a".
a/sin 81 = 4.76/sin 50
a = 6.14 km
B) distance between first and third building is AB in the triangle depicted by "b".
Similar to the first problem, we will use sine rule again.
b/sin49 = 4.76/sin 50
b = 4.69 km
