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bearhunter [10]
3 years ago
7

Does the mass of a pendulum affects the period of oscillation

Physics
1 answer:
pshichka [43]3 years ago
8 0
Mass does not affect the pendulum's swing. The longer the length of string, the farther the pendulum falls; and therefore, the longer the period, or back and forth swing of the pendulum. The greater the amplitude, or angle, the farther the pendulum falls; and therefore, the longer the period.
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An electric field of magnitude 2.35 V/m is oriented at an angle of 25.0° with respect to the positive z-direction. Determine the
zzz [600]

Answer:

The magnitude of the electric flux is 3.53\ N-m^2/C

Explanation:

Given that,

Electric field = 2.35 V/m

Angle = 25.0°

Area A= 1.65 m^2

We need to calculate the flux

Using formula of the magnetic flux

\phi=E\cdot A

\phi = EA\cos\theta

Where,

A = area

E = electric field

Put the value into the formula

\phi=2.35\times1.65\times\cos 25^{\circ}

\phi=2.35\times1.65\times0.91

\phi=3.53\ N-m^2/C

Hence, The magnitude of the electric flux is 3.53\ N-m^2/C

8 0
3 years ago
What instrument is used to expand burr holes?
k0ka [10]
Craniotomes are used
4 0
3 years ago
A graph shows how the temperature of a substance changes as energy is added steadily over time.
OlgaM077 [116]

Answer:

A flat, horizontal line  

Explanation:

A flat, horizontal line indicates a phase change.

The temperature does not increase because the added heat goes into converting one phase into another.

A is wrong. A downward-sloping line indicates that the temperature is decreasing with time.

C is wrong. An upward-sloping line indicates that the temperature is increasing with time.

8 0
3 years ago
Read 2 more answers
Explain why pumice floats and why ironwood sinks
almond37 [142]

Answer:

A quick way of describing density is to describe an object as heavy or light for its size. Pumice stone, unlike regular rock, does not sink in water because it has a low density. An ironwood branch is very dense and sinks in water.

Hope that helps. x

6 0
2 years ago
Read 2 more answers
A shot-putter released the shot at an angle of 41.5 degrees and a height of 1.9 m with an initial velocity of 13.3 m/s. How far
liq [111]

Answer:

x = 17.88[m]

Explanation:

We can find the components of the initial velocity:

(v_{x})_{o}  = 13.3*cos(41.5)=9.96[m/s]\\(v_{y})_{o}  = 13.3*sin(41.5)=8.81[m/s]

We have to remember that the acceleration of gravity will be worked with negative sign, since it acts in the opposite direction to the movement in direction and the projectile upwards.

g = - 9.81[m/s^2]

Now we must find the time it takes for the projectile to hit the ground, as the problem mentions that it does not impact on the board.

y=y_{o} +(v_{y} )_{o} *t-0.5*g*(t)^{2} \\0=1.9+(8.81*t)-(4.905*t^{2})\\-1.9=8.81*t*(1-0.5567*t)\\t=0\\t=1.796[s]

With this time we can calculate the horizontal distance:

x=(v_{x})_{o} *t\\x=9.96*1.796\\x=17.88[m]

3 0
3 years ago
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