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Helga [31]
3 years ago
11

If you double the dimensions of a cube what happens to the volume

Physics
1 answer:
Triss [41]3 years ago
8 0
By definition, a cube is a three-dimensional figure that have equal dimensions for all its sides. It comprises of two square bases, one on top and one on the bottom. The face sides are also squares. Therefore, the volume of a cube is equal to s³, where s is the measure of the side's length. To compare the change, let us assume values. First, suppose s=1. Then, we denote this volume as V₁.

V₁ = (1)³ = 1

Next, taking the double, s=2. The volume for this is denoted as V₂.

V₂ = (2)³ = 8

Taking the ratio of V₂ to V₁:

V₂/V₁ = 8

That means the scale factor is 8. When the side dimensions is doubled, the volume of the cube increases 8 times as great as the original volume.
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6 0
3 years ago
A 34-m length of wire is stretched horizontally between two vertical posts. The wire carries a current of 68 A and experiences a
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Answer:

7.28×10⁻⁵ T

Explanation:

Applying,

F = BILsin∅............. Equation 1

Where F = magnetic force, B = earth's magnetic field, I = current flowing through the wire, L = Length of the wire, ∅ = angle between the field and the wire.

make B the subject of the equation

B = F/ILsin∅.................. Equation 2

From the question,

Given: F = 0.16 N, I = 68 A, L = 34 m, ∅ = 72°

Substitute these values into equation 2

B = 0.16/(68×34×sin72°)

B = 0.16/(68×34×0.95)

B = 0.16/2196.4

B = 7.28×10⁻⁵ T

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3 years ago
While standing atop a building 49.6 m tall, you spot a friend standing on a street corner. Using a protractor and a dangling plu
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3 years ago
Calculate the mass number of an atom with 8 protons, 12 neutrons and 10 electrons
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3 years ago
A student at another university repeats the experiment you did in lab. Her target ball is 0.860 m above the floor when it is in
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Answer:

K = 0.076 J

Explanation:

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The mass of the steel ball, m = 0.0120 kg

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We need to find the kinetic energy (in joules) of the target ball just after it is struck. Let t is the time taken by the ball to reach the ground.

h=ut+\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}}

Put all the values,

t=\sqrt{\dfrac{2\times 0.860 }{9.8}} \\\\=0.418\ s

The velocity of the ball is :

v=\dfrac{1.5}{0.418}\\\\= $$3.58\ m/s

The kinetic energy of the ball is :

K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 0.0120\times 3.58^2\\\\=0.076\ J

So, the required kinetic energy is 0.076 J.

6 0
3 years ago
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