Answer:
Explanation:
Given that
The mass of the body is 0.04kg
M=0.04kg
The radius of the paths is 0.6m
r=0.6m
The normal force exerted at A is 3.9N
Fa=3.9N
The normal force exerted at B is 0.69N
Fb=0.69N
Then work done by friction from point A to B will be the change in K.E
W=∆K.E+P.E
So we need to know the velocity at both point A and B
Then since the centripetal force is given as
Ft=mv²/r
Then,
For point A
Fa=mv²/r
3.9=0.04v²/0.6
3.9=0.0667v²
v²=3.9/0.0667
v²=58.5
v=√58.5
v=7.65m/s
Va=7.65m/s
Now at point B
Fb=mv²/r
0.69=0.04v²/0.6
0.69=0.0667v²
v²=0.69/0.0667
v²=10.35
v=√10.35
v=3.22m/s
Vb=3.22m/s
Then, the work done is
W=∆K.E+P.E
P.E is given as mgh
The height will be 2R =1.2m
P.E=mgh
P.E=0.04×9.81×1.2
P.E=0.471J
Final kinetic energy at B minus initial kinetic energy at A
W=K.Eb-K.Ea
K.E is given as 1/2mv²
W=1/2m(Vb²-Va²) +P.E
W=0.5×0.04(3.22²-7.65²) +0.471
W=0.5×0.04×(-48.1541) +0.471
W=-0.96+0.471
W=-0.49J
work was done on the block by friction during the motion of the block from point A to point B is 0.49J.
Friction opposes motions and that is why the work done is negative
Answer:
According to the Conservation of Momentum,
Momentum of the gun = momentum of the bullet
M(gun)×V(gun)=m(bullet)×v(bullet)
4kg × V = 0.3kg × 600m/s²
V = (0.3 × 600)/4 = 45 m/s
The recoil velocity on the gun is <em><u>45 m/s</u></em>
<h3><u>45 m/s</u> is the right answer.</h3>
The answer is "matter is made up of tiny particles called atoms"
Newton's first law of motion states that an object that is resting (not moving) will stay motionless unless an external force acts on it and an object in motion will stay in motion unless an outside force acts on it. This law is known as newton's law of inertia.
Answer:
a) The magnitude of the current is 24.19 A
b) The angle is 90°
Explanation:
a) Given:
B = magnetic field = 44 µT = 44x10⁻⁶T
r = distance = 11 cm = 0.11 m
The current is:
b) Because the current flows from the west to the east, therefore, the angle is 90 degrees from the north.
