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Snowcat [4.5K]
2 years ago
7

Dina has a mass of 50 kilograms and is waiting at the top of a ski slope that’s 5.0 meters high.

Physics
2 answers:
Over [174]2 years ago
8 0
All of Dina's potential energy Ep is converted into kinetic energy Ek so Ep=Ek, where Ep=m*g*h and Ek=(1/2)*m*v². m is the mass of Dina, h is the height of ski slope, g=9.8 m/s² and v is the maximal velocity. 

So we solve for v:

m*g*h=(1/2)*m*v², masses cancel out,

g*h=(1/2)*v², we multiply by 2,

2*g*h=v² and take the square root to get v

√(2*g*h)=v, we plug in the numbers and get:

v=9.9 m/s. 

So Dina's maximum velocity on the bottom of the ski slope is v=9.9 m/s.
ivann1987 [24]2 years ago
8 0

Answer:

All of Dina's potential energy Ep is converted into kinetic energy Ek so Ep=Ek, where Ep=m*g*h and Ek=(1/2)*m*v². m is the mass of Dina, h is the height of ski slope, g=9.8 m/s² and v is the maximal velocity. 

So we solve for v:

m*g*h=(1/2)*m*v², masses cancel out,

g*h=(1/2)*v², we multiply by 2,

2*g*h=v² and take the square root to get v

√(2*g*h)=v, we plug in the numbers and get:

v=9.9 m/s. 

So Dina's maximum velocity on the bottom of the ski slope is v=9.9 m/s.

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Regarding the ratio work output to work input:

\frac{WO}{WI} < 1

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The manufacturer of a 6V dry-cell flashlight battery says that the battery will deliver 15 mA for 60 continuous hours. During th
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Answer:

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Answer:

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Hope this helps you

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