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3 years ago

15

How can 3 tents be 40 dollars

1 answer:

nasty-shy [4]3 years ago

5 0

I'm assuming this is a math question and all the tents equal the same thing, so to find the price for one tent, we would divide 40/3

Each tent is about $13.33

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The distance from carries house to the park was 3/4 of a mile. Carrie walked 2/3 of the way before she stop for a drink . How fa

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Carrie walked 1/2 mile.

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3 years ago

The volume of a right circular cone with radius r and height h is V = pir^2h/3.

Scorpion4ik [409]

The question is incomplete. The complete question is :

The volume of a right circular cone with radius r and height h is V = pir^2h/3. a. Approximate the change in the volume of the cone when the radius changes from r = 5.9 to r = 6.8 and the height changes from h = 4.00 to h = 3.96.

b. Approximate the change in the volume of the cone when the radius changes from r = 6.47 to r = 6.45 and the height changes from h = 10.0 to h = 9.92.

a. The approximate change in volume is dV = _______. (Type an integer or decimal rounded to two decimal places as needed.)

b. The approximate change in volume is dV = ___________ (Type an integer or decimal rounded to two decimal places as needed.)

Solution :

Given :

The volume of the right circular cone with a radius r and height h is

$V=\frac{1}{3} \pi r^2 h$

$dV = d\left(\frac{1}{3} \pi r^2 h\right)$

$dV = \frac{1}{3} \pi h \times d(r^2)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

a). The radius is changed from r = 5.9 to r = 6.8 and the height is changed from h = 4 to h = 3.96

So, r = 5.9 and dr = 6.8 - 5.9 = 0.9

h = 4 and dh = 3.96 - 4 = -0.04

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (5.9)(4)(0.9)+\frac{1}{3} \pi (5.9)^2 (-0.04)$

$dV=44.484951 - 1.458117$

$dV=43.03$

Therefore, the approximate change in volume is dV = 43.03 cubic units.

b). The radius is changed from r = 6.47 to r = 6.45 and the height is changed from h = 10 to h = 9.92

So, r = 6.47 and dr = 6.45 - 6.47 = -0.02

h = 10 and dh = 9.92 - 10 = -0.08

Now, $dV = \frac{2}{3} \pi r h (dr)+\frac{1}{3} \pi r^2 dh$

$dV = \frac{2}{3} \pi (6.47)(10)(-0.02)+\frac{1}{3} \pi (6.47)^2 (-0.08)$

$dV=-2.710147-3.506930$

$dV= -6.22$

Hence, the approximate change in volume is dV = -6.22 cubic units

8 0

3 years ago

A line segment has endpoints at (–1, 4) and (4, 1). Which reflection will produce an image with endpoints at (–4, 1) and (–1, –4

Ivahew [28]

Answer:

A

Step-by-step explanation:

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3 years ago

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The sum of the lengths of the two bases of a trapezoid is 22 cm and its area is 66 cm2.

ludmilkaskok [199]

Answer:

h = 6 cm

Step-by-step explanation:

Given that,

The area of a trapezoid, A = 66 cm²

The sum of the lengths of the two bases of a trapezoid is 22 cm.

We need to find the height of the trapezoid.

The area of a trapezium is given by :

$A=\dfrac{1}{2}\times (\text{sum of parallel sides})\times \text{height}$

Substitute the values,

$h=\dfrac{2A}{\text{sum of parallel sides}}\\\\h=\dfrac{2\times 66}{22}\\\\h=6\ cm$

So, the height of the trapezoid 6 cm.

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3 years ago

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3 years ago