D I believe. Correct me if I’m wrong.
Answer:
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10
Explanation:
To write the configuration for the Silver and the Silver ion, first we need to write the electron configuration for just Silver (Ag). We first need to find the number of electrons for the Ag atom (there are 47 electrons) using the Periodic Table. When we write the configuration, we'll put all 47
Either way, the Silver electron configuration will be 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s1
Note that when writing the electron configuration for an atom like Ag and Ag+, the 4d is usually written before the 5s. Both of the configurations have the correct numbers of electrons in each orbital, it is just a matter of how the electronic configuration notation is written (see below for an explanation why).
For the Ag+, called the Silver ion, we remove one electron from 5s2 leaving us with:
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10
Answer:
<em>If two(or more) forces act on an object in the same direction, the net force is the sum of the forces. In the diagram at left, the net force is 30 Newtons to the right</em>
Answer:
The number of electrons in the outermost shell of an atom determines its reactivity. Noble gases have low reactivity because they have full electron shells. Halogens are highly reactive because they readily gain an electron to fill their outermost shell.
Explanation:
they have a negligible mass and they also have a negative charge so they have an association with the magnetic field. Do you remember polar? So electrons are negative and they attract the nucleus which is overall postivie (since protons are positive) so they act as magnetic since they both have an attraction