Question

Question 2 (1 point)

Answer 1

The car takes 10.8 seconds to reach a velocity of 42.1 m/s

Explanation:

The motion of the car is at constant acceleration, so we can use the following suvat equation:

$v=u+at$

where

v is the final velocity of the car

u is its initial velocity

a is the acceleration

t is the time

For the car in this problem, we have:

u = 15.0 m/s

v = 42.1 m/s

$a=2.50 m/s^2$

Solving for t, we find the time it takes for the car to reach that velocity:

$t=\frac{v-u}{a}=\frac{42.1-15.0}{2.50}=10.8 s$

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