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kobusy [5.1K]
3 years ago
6

A car with an initial velocity of 5.0 is acelerated at 3.0for 4.0seconds what os the velocity of tje car ofter the 4.0seconds

Physics
1 answer:
sasho [114]3 years ago
6 0
Vf =Vi+at
Vf= 5 + 3*4
Vf=5+12
Vf=17m/sec
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The conclusion that is best supported by the data is;

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Suppose you hit a steel nail with a 0.500-kg hammer, initially moving at 15.0 m/s and brought to rest in 2.80 mm. How much is th
katrin [286]

Complete Question

Suppose you hit a steel nail with a 0.500-kg hammer, initially moving at 15.0 m/s and brought to rest in 2.80 mm. How much is the nail compressed if it is 2.50 mm in diameter and 6.00-cm long.What Average force is excreted on the Nail

Answer:

F=2*10^{4}N

Explanation:

From the question we are told that:

Mass m=0.500kg

Initial Velocity V=15.0m/s

Distance x=2.80mm=>0.00280m

Diameter d=2.50mm=>0.00250m

Length l=6.00cm=>0.6m

Generally the equation for Force is mathematically given by

 F=\frac{mv^2}{2d}

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 F=2*10^{4}N

6 0
3 years ago
Could we see a galaxy that is 20 billion light-years away?.
vichka [17]

Answer:

No

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20 billion light-years away are beyond our sight and perspective on Earth and wouldn't be observable in our universe.

7 0
2 years ago
Lenz's Law: A coil lies flat on a tabletop in a region where the magnetic field vector points straight up. The magnetic field va
julia-pushkina [17]

Answer:

Explanation:

The magnetic field is straight up. It is reducing . As per Lenz's law , direction of induced current is such that it opposes the reason which creates it . magnetic field in upper direction is reducing . So current will be such that magnetic field produced by it increases magnetic field in upper direction . In other words , induced current should create magnetic field in upward direction. It is possible when direction of induced current is  anti - clockwise,  when seen from above.

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3 years ago
A high-jump athlete leaves the ground, lifting her center of mass 1.8 m and crossing the bar with a horizontal velocity of 1.4 m
Romashka [77]

Answer:

The minimum speed when she leave the ground is 6.10 m/s.

Explanation:

Given that,

Horizontal velocity = 1.4 m/s

Height = 1.8 m

We need to calculate the minimum speed must she leave the ground

Using conservation of energy

K.E+P.E=P.E+K.E

\dfrac{1}{2}mv_{1}^2+0=mgh+\dfrac{1}{2}mv_{2}^2

\dfrac{v_{1}^2}{2}=gh+\dfrac{v_{2}^2}{2}

Put the value into the formula

\dfrac{v_{1}^2}{2}=9.8\times1.8+\dfrac{(1.4)^2}{2}

\dfrac{v_{1}^2}{2}=18.62

v_{1}=\sqrt{2\times18.62}

v_{1}=6.10\ m/s

Hence, The minimum speed when she leave the ground is 6.10 m/s.

6 0
3 years ago
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