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kobusy [5.1K]
3 years ago
6

A car with an initial velocity of 5.0 is acelerated at 3.0for 4.0seconds what os the velocity of tje car ofter the 4.0seconds

Physics
1 answer:
sasho [114]3 years ago
6 0
Vf =Vi+at
Vf= 5 + 3*4
Vf=5+12
Vf=17m/sec
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While researching scuba diving, Pablo reads how hot a tank should get while being filled with air. Which law best explains why t
Lady_Fox [76]

Answer:

Gay-Lussac’s law, because as the pressure increases, the temperature increases

Explanation:

First of all, we can notice that the volume of the tank is fixed: this means that the volume of the air inside is also fixed.

This means that in this situation we can apply Gay-Lussac's law, which states that:

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Mathematically:

p\propto T

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5 0
2 years ago
Read 2 more answers
A car with an initial velocity of 5.0 is acelerated at 3.0for 4.0seconds what os the velocity of tje car ofter the 4.0seconds
sasho [114]
Vf =Vi+at
Vf= 5 + 3*4
Vf=5+12
Vf=17m/sec
6 0
3 years ago
A point charge of 5.7 µc moves at 4.5 × 105 m/s in a magnetic field that has a field strength of 3.2 mt, as shown in the diagram
Sauron [17]

The magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N

<h3>What is magnetic force?</h3>

Magnetic force, attraction or repulsion that arises between electrically charged particles because of their motion.The magnitude of the magnetic force acting on the charge is given by:

\rm F=qvBsin\theta

where

The magnitude of the charge   q=5.7\ \mu C =5.7\times 10^{-6} \ C

The velocity of the charge        v=4.5\times 10^5\ \frac{m}{s}

The magnitude of the magnetic field   3.2\ mT=0.0032\ T

The angle between the directions of v and B  \theta =90^o-37^o=53^o

By substituting the values we will get:

F=(5.7\times 10^}-6})(4.5\times 10^5)(0.0032)(Sin53^o)

F=6.6\times 10^{-3}\ N

Hence the magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N

To know more about Magnetic force follow

brainly.com/question/14411049

3 0
2 years ago
the resistance of a wire of length 80cm and of uniform area of cross-section 0.025cmsq., is found to be 1.50 ohm. Calculate spec
vivado [14]
Specific\ resistance\ =resistivity\\&#10;From\ formula\ on \ resistance:\ R= \frac{pL}{A}\ p-resistivity,\ L-length,\\ A-area\ of\ cross\ section\\&#10;p= \frac{R*A}{L}= \frac{1,5Ohm*0,025*10^{-4}m^2 }{80* 10^{-2}m }=0,0003515625 Ohm*m
3 0
3 years ago
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