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ololo11 [35]
3 years ago
8

Select the statement that best describes gravity.

Physics
2 answers:
ch4aika [34]3 years ago
6 0

Answer:

Gravity is the force of attraction between two objects; it is dependent upon the mass of the objects and the distance between the objects.

Explanation:

Gravity is defined as the force of attraction between two objects. It depends on the masses of objects and the distance between them. The gravitational force between two bodies is given by the universal law of gravitation. According to this law, the force of gravity is :

F=G\dfrac{m_1m_2}{d^2}

Where

G is the universal gravitational constant

m₁ and m₂ are masses of two bodies

d is the distance between two bodies

Hence, the correct statement that describes gravity is (b)

Tcecarenko [31]3 years ago
5 0

Answer:

The answer is Gravity is the force of attraction between two objects; it is dependent upon the mass of the objects and the distance between the objects.

Explanation:

Gravity is a natural phenomenon by which objects with mass are attracted to each other, mostly observable in the interaction between planets, galaxies and other objects in the universe. It is one of the four fundamental interactions that causes the acceleration experienced by a physical body in the vicinity of an astronomical object. It is also called gravitational interaction or gravitation.

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A 70-kg pole vaulter running at 11 m/s vaults over the bar. Her speed when she is above the bar is 1.3 m/s. Neglect air resistan
yKpoI14uk [10]

Answer:

h_{B} = 6.083\,m

Explanation:

Let assume that pole vaulter begins running at a height of zero. The pole vaulter is modelled after the Principle of Energy Conservation:

K_{A} = K_{B} + U_{g,B}

\frac{1}{2}\cdot m \cdot v_{A}^{2} = \frac{1}{2}\cdot m \cdot v_{B}^{2} + m\cdot g \cdot h_{B}

The expression is simplified and final height is cleared within the equation:

\frac{1}{2}\cdot (v_{A}^{2} - v_{B}^{2}) = g\cdot h_{B}

h_{B} = \frac{(v_{A}^{2}-v_{B}^{2})}{2\cdot g}

h_{B} = \frac{[(11\,\frac{m}{s} )^{2}-(1.3\,\frac{m}{s} )^{2}]}{2\cdot (9.807\,\frac{m}{s^{2}} )}

h_{B} = 6.083\,m

5 0
3 years ago
Please help!!! give me a summary on why human population is either good or bad!! thank youu
bagirrra123 [75]
It is bad because humans are destroying the planet with pollution and cutting down natural habitats. This is not only killing the human population in the future, but as of right now they are killing animals, and trees. The human population is slowly destroying the planet.
7 0
2 years ago
A 69.5-kg person throws a 0.0475-kg snowball forward with a ground speed of 31.5 m/s. A second person, with a mass of 57.5 kg, c
Leno4ka [110]

Answer:

- After throwing the snow, velocity of the thrower is 2.33 m/s

- the velocity of the receiver is 0.026 m/s

Explanation:

Given the data in the question;

Using conservation of momentum,

Initial thrower has a momentum of mv; m_{totalv

(69.5 kg + 0.0475 kg) × 2.35 m/s = 163.4366 kg.m/s

Now, When he throws it at 31.5 m/s, these constitutes a momentum of;

(0.0475 kg )(31.5 m/s) = 1.49625 kg.m/s

hence his momentum now is: 163.4366 - 1.49625 = 161.94035 kg.m/s

To get his velocity, we say;

161.94035 = mv

{ he lost weight of the snow ball so, m = 69.5 kg )

161.94035 = 69.5 × v

v = 161.94035 / 69.5

v = 2.33 m/s

Therefore, After throwing the snow, velocity of the thrower is 2.33 m/s

Next is the Receiver;

the receiver will gain momentum of 1.49625 kg.m/s

he has no momentum initially and after he catches the snow ball;

1.49625 kg.m/s = mv

1.49625 kg.m/s = ( 57.5 kg +  0.0475 kg ) × v

1.49625 kg.m/s = 57.5475 kg × v

v = ( 1.49625 kg.m/s ) / 57.5475 kg

v = 0.026 m/s

Therefore, the velocity of the receiver is 0.026 m/s

3 0
3 years ago
The net force is 180 and the mass is 1.793 what is the acceleration
nata0808 [166]

Answer:

100.390407

Explanation:

To find acceleration, you would use the formula a=f/m (acceleration equals force divided by mass) and then once you enter those numbers in the formula, a=180/1.793. Then you divide 180 divided by 1.793 which gets you an answer of 100.390407.

6 0
3 years ago
A 2100 g block is pushed by an external force against a spring (with a 22 N/cm spring constant) until the spring is compressed b
Vilka [71]

Answer:

6.5e-4 m

Explanation:

We need to solve this question using law of conservation of energy

Energy at the bottom of the incline= energy at the point where the block will stop

Therefore, Energy at the bottom of the incline consists of the potential energy stored in spring and gravitational potential energy=\frac{1}{2} kx^{2} +PE1

Energy at the point where the block will stop consists of only gravitational potential energy=PE2

Hence from Energy at the bottom of the incline= energy at the point where the block will stop

⇒\frac{1}{2} kx^{2} +PE1=PE2

⇒PE2-PE1=\frac{1}{2} kx^{2}

Also PE2-PE2=mgh

where m is the mass of block

g is acceleration due to gravity=9.8 m/s

h is the difference in height between two positions

⇒mgh=\frac{1}{2} kx^{2}

Given m=2100kg

k=22N/cm=2200N/m

x=11cm=0.11 m

∴2100*9.8*h=\frac{1}{2}*2200*0.11^{2}

⇒20580*h=13.31

⇒h=\frac{13.31}{20580}

⇒h=0.0006467m=6.5e-4

7 0
3 years ago
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