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Masja [62]
3 years ago
10

The diagram shows how air circulation forms a sea breeze on a warm day. A beach meets the sea in the middle of the image with a

blue sky above containing a bright sun. On top above the water is A pair of arrows changing from red to blue pointing right toward the sea labeled 1 Return Flow. Then a blue arrow points down over the sea labeled 2 Cool. Then a pair of arrows going from blue to red point left labeled 3 Sea Breeze. Then a red arrow points up over the sand labeled 4 Warm. Which best describes what is happening in the diagram? At point 1, the air in the convection current is warmer and denser than at point 3 because its molecules contain more kinetic energy. At point 2, the air absorbs thermal energy from the surrounding air, which causes it to become heavier and sink. At point 3, the air in the convection current is cooler and lighter than the air in other parts of the current, so it is preparing to rise. At point 4, thermal energy from warm air over the land is transferred upward toward cooler areas of the atmosphere
Physics
2 answers:
nadezda [96]3 years ago
7 0
Yes it was then a red left label
Mkey [24]3 years ago
3 0

Answer:

D

Explanation:

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At a given time of​ day, the ratio of the height of an object to the length of its shadow is the same for all objects. If a 4​-f
katrin2010 [14]

Answer:35.2 ft

Explanation:

Given

height of stick =4 ft

shadow length =2.8 ft

Angle of elevation of sun is

tan\theta =\frac{4}{2.8}

let the height of tree be h

as \thetawill remain same thus

tan\theta =\frac{h}{24.64}

\frac{4}{2.8}=\frac{h}{24.64}

h=35.2 ft

8 0
3 years ago
A train car has a mass of 10,000 kg and is moving at +3.0 m/s. It strikes an identical train car that is at rest. The train cars
VLD [36.1K]
In order to compute the final velocity of the trains, we may apply the principle of conservation of momentum which is:
initial momentum = final momentum
m₁v₁ = m₂v₂

The final mass of the trains will be:
10,000 + 10,000 = 20,000 kg
Substituting the values into the equation:

10,000 * 3 = 20,000 * v
v = 1.5 m/s

The final velocity of the trains will be 1.5 m/s
6 0
3 years ago
While standing at the edge of the roof of a building, a man throws a stone upward with an initial speed of 6.95 6.95 m/s. The st
qwelly [4]

Answer:

18.1347 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s² = a

v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-6.95^2}{2\times -9.81}\\\Rightarrow s=2.4619\ m

Total height the ball falls is 2.4619+14.3 = 16.7619 m

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 16.7619+0^2}\\\Rightarrow v=18.1347\ m/s

The speed at which the stone reaches the ground is 18.1347 m/s

8 0
3 years ago
Through what process is carbon pulled from the atmosphere in the carbon cycle
Andrei [34K]

Carbon is pulled from the atmosphere in the carbon cycle through the process of photosynthesis. Details about photosynthesis can be found below.

<h3>What is photosynthesis?</h3>

Photosynthesis is the process whereby green plants obtain their nutrition by utilizing energy from sunlight.

Green plants absorb carbon in the form of carbon dioxide from the atmosphere and use it in the photosynthetic process.

This means that one way that carbon is removed from the atmosphere during the carbon cycle is through photosynthesis.

Learn more about photosynthesis at: brainly.com/question/1388366

#SPJ1

7 0
2 years ago
Suppose that a meter stick is balanced at its center.  A 0.24 kg mass is then positioned at the 6-cm mark.   At what cm mark mus
Scilla [17]

Answer:

80.17 cm

Explanation:

Taking moments of forces about the center, the total clockwise moments is equal to the total counter clockwise moment:

Force * distance (counter clockwise) = force * distance (clockwise)

0.24 * 9.8 * (50 - 6) = 0.35 * 9.8 * (x - 50)

0.24 * 44 = 3.43x - 171.5

103.5 = 3.43x - 171.5

=> 3.43x = 103.5 + 171.5

3.43x = 275

x = 275/3.43 = 80.17 cm

8 0
3 years ago
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