The answer is C. p=mv p=18x30 = 540kgm/s
Answer:
289282
Explanation:
r = Radius of plate = 0.52 mm
d = Plate separation = 0.013 mm
A = Area = 
V = Potential applied = 2 mV
k = Dielectric constant = 40
= Electric constant = 
Capacitance is given by
Charge is given by
Number of electron is given by
The number of charge carriers that will accumulate on this capacitor is approximately 289282.
Answer:
A₁/A₂ = 0.44
Explanation:
The emissive power of the bulb is given by the formula:
P = σεAT⁴
where,
P = Emissive Power
σ = Stefan-Boltzman constant
ε = Emissivity
A = Surface Area
T = Absolute Temperature of Surface
<u>FOR BULB 1:</u>
Since, emissivity and emissive power are constant.
Therefore,
P = σεA₁T₁⁴ ----------- equation 1
where,
A₁ = Surface Area of Bulb 1
T₁ = Temperature of Bulb 1 = 3000 k
<u>FOR BULB 2:</u>
Since, emissivity and emissive power are constant.
Therefore,
P = σεA₂T₂⁴ ----------- equation 2
where,
A₂ = Surface Area of Bulb 2
T₂ = Temperature of Bulb 1 = 2000 k
Dividing equation 1 by equation 2, we get:
P/P = σεA₁T₁⁴/σεA₂T₂⁴
1 = A₁(3000)²/A₂(2000)²
A₁/A₂ = (2000)²/(3000)²
<u>A₁/A₂ = 0.44</u>
Answer:
1. the voltage will be 2.35×12.5 = 29.4V
2. the resistance would be 9.0/6.2= 1.45ohms
3. in series they will add up thus 4+8+12= 24ohms
4. in parallel it will be 2.18ohms
B.) The retina is the layer containing t<span>he light sensing nerve cells (rods and cones)
The lens helps the eye focus light on the retina, the cornea is the outer transparent structure that covers the iris and helps the eye focus, and the pupil is the opening through which light enters the eye.</span>
