There are 60 seconds in a minute.
This means that 5 minutes would be 60 times 5.
60×5 = 300
There are 300 seconds in 5 minutes.
Density reduces
Explanation:
The density of a fluid will reduce as a substance gains more thermal energy. Heat is a form of thermal energy usually noticed as temperature differences in a matter.
- When thermal energy is gained by a body, the temperature of the body rises.
- The particles of the medium gains more kinetic energy.
- This causes the substance to expand and it has more volume.
- When a substance expands, it occupies more space.
- The more the volume a body occupies, the lesser the density.
- Expansion does not change the mass of the fluid but the volume changes.
- This is why density decreases.
Learn more:
Density brainly.com/question/8441651
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Answer:

Explanation:
The total energy of the satellite when it is still in orbit is given by the formula

where
G is the gravitational constant
m = 525 kg is the mass of the satellite
is the Earth's mass
r is the distance of the satellite from the Earth's center, so it is the sum of the Earth's radius and the altitude of the satellite:

So the initial total energy is

When the satellite hits the ground, it is now on Earth's surface, so

so its gravitational potential energy is

And since it hits the ground with speed

it also has kinetic energy:

So the total energy when the satellite hits the ground is

So the energy transformed into internal energy due to air friction is the difference between the total initial energy and the total final energy of the satellite:

Answer:
0.872<em>m/s</em>
Explanation:
Tangential velocity is given by the formula,

In the question given,
radius= 25meters
time= 180secs
pie= 3.14
number of laps= 1
The magnitude of tangential velocity equals;

<em>v </em>= 157<em>m</em>/180<em>secs</em>
Therefore, the magnitude of the tangential velocity
=0.872<em>m/secs</em>