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2 years ago

1. Un cable está tendido sobre dos postes colocados con una separación de 10,0 m. A la

Physics

1 answer:

ale4655 [162]2 years ago

7 0

Explanation:

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Inez uses hairspray on her hair each morning before going to school. The spray spreads out before reaching her hair partly becau

Tamiku [17]

Answer:

$7.0\cdot 10^{-13}C$

Explanation:

The magnitude of the electrostatic force between two charged objects is

$F=k\frac{q_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1 and q2 are the two charges

r is the separation between the two charges

The force is attractive if the charges have opposite sign and repulsive if the charges have same sign.

In this problem, we have:

$r=0.070 cm =7\cdot 10^{-4} m$ is the distance between the charges

$q_1=q_2=q$ since the charges are identical

$F=9.0\cdot 10^{-9}N$ is the force between the charges

Re-arranging the equation and solving for q, we find the charge on each drop:

$F=\frac{kq^2}{r^2}\\q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(9.0\cdot 10^{-9})(7\cdot 10^{-4})^2}{8.99\cdot 10^9}}=7.0\cdot 10^{-13}C$

8 0

3 years ago

In a thunderstorm, electric charge builds up on the water droplets or ice crystals in a cloud. Thus, the charge can be considere

muminat

Answer:

$2.1\cdot 10^{21}$ electrons

Explanation:

The magnitude of the electric field outside an electrically charged sphere is given by the equation

$E=\frac{kQ}{r^2}$

where

k is the Coulomb's constant

Q is the charge stored on the sphere

r is the distance (from the centre of the sphere) at which the field is calculated

In this problem, the cloud is assumed to be a charged sphere, so we have:

$E_b=3.00\cdot 10^6 N/C$ is the maximum electric field strength tolerated by the air before breakdown occurs

$r=1.00 km = 1000 m$ is the radius of the sphere

Re-arranging the equation for Q, we find the maximum charge that can be stored on the cloud:

$Q=\frac{Er^2}{k}=\frac{(3.00\cdot 10^6)(1000)^2}{9\cdot 10^9}=333.3 C$

Assuming that the cloud is negatively charged, then

$Q=-333.3 C$

And since the charge of one electron is

$e=-1.6\cdot 10^{-19}C$

The number of excess electrons on the cloud is

$N=\frac{Q}{e}=\frac{-333.3}{-1.6\cdot 10^{-19}}=2.1\cdot 10^{21}$

5 0

3 years ago

Scientists want to place a telescope on the moon to improve their view of distant planets. The telescope weighs 200 pounds on Ea

Maru [420]

Answer:

33,02 lb

Explanation:

g_m ≈ 1,62 m/s2

g ≈ 9,81 m/s2

m = 200 lb

m_m = m * g_m / m = 200 * 1,62 / 9,81 = 33,02 lb

7 0

3 years ago

Read 2 more answers

A 2 kg picture frame sits on a shelf at a height of 0.5 m. how much gravitational potential energy is added to the picture frame

AysviL [449]

The change in gravitational potential energy is A) 15.68 J

Explanation:

The gravitational potential energy of an object is the energy possessed by the object due to its position in the gravitational field.

The change in gravitational potential energy of an object is given by the equation:

$\Delta U = mg\Delta h$

where

m is the mass of the object

$g=9.8 m/s^2$ is the acceleration due to gravity

$\Delta h$ is the change in height of the object

In this problem, we have

m = 2 kg is the mass of the frame

$\Delta h = 1.3 - 0.5 = 0.8 m$ is the change in height

Substituting, we find:

$\Delta U = (2)(9.8)(0.8)=15.68 J$

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

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3 years ago

A toy car sits motionless at the top of a ramp. What will happen to the car if a balanced force acts upon it?

dexar [7]

Answer:

kinetic energy because when the car moves again it will be faster then it was before

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2 years ago